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2 years ago

Write the equation in standard form. 8−5y=−2x

Mathematics

2 answers:

Elena-2011 [213]2 years ago

7 0

Answer:

-5y+2x=-8

Step-by-step explanation:

8-5y=-2x

move the 8 to the right..

-5y=-2x-8

move the -2x to the left..

-5y+2x=-8!

Hope if helps :D

GarryVolchara [31]2 years ago

6 0

8-5y= -2x
⇒ -5y= -2x-8
⇒ y= -2/(-5)x -8/(-5)
⇒ y= 2/5x+ 8/5

The final answer is y= 2/5x+ 8/5~

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inna [77]

$\qquad\qquad\huge\underline{\boxed{\sf Answer☂}}$

let's simplify ~

$\qquad \sf \dashrightarrow \: \sqrt{5} (10 - 4 \sqrt{2} )$

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1 year ago

Easy question. Solve the inequality -5x<40

laiz [17]

$\huge\text{Hey there!}$

$\mathsf{-5x < 40}$

$\large\text{DIVIDE -5 to BOTH SIDES}$

$\mathsf{\dfrac{-5x}{-5}$

$\rm{CANCEL\ out: \dfrac{-5}{-5} \ because\ that \ gives\ you\ 1}$

$\rm{KEEP: \dfrac{40}{-5}\ because \ that \ gives \ you \ what \ you \ are\ comparing}\\\\\rm{to \ the \ x-value}$

$\mathsf{\dfrac{40}{-5}=\boxed{\bf -8}}$

$\mathsf{x > -8}$

$\boxed{\boxed{\large\textsf{Answer: \large \bf x }\bf > \large\textsf{\bf -8}}}\huge\checkmark$

$\boxed{\large\textsf{IT is an O(P)(E)(N)(E)(D) circle shaded to the right}}$

$\large\text{Good luck on your assignment and enjoy your day!}$

~ $\frak{Amphitrite1040:)}$

3 0

3 years ago

PLEASE HELP ILL MARK YOU THE BRAINLIEST ASAP!!

Ratling [72]

Answer:

second 1 is right

Step-by-step explanation:

it is righttttt

4 0

2 years ago

Read 2 more answers

Solve inequality in interval notation Y^2>-5y-9

nata0808 [166]

It’s going to be negative infinitely, infinitely.

4 0

2 years ago

PLS HELP ME WITH THIS!!!!!! HOW DID THEY GET 80ft^2

noname [10]

$\huge \boxed{\mathfrak{Question} \downarrow}$

Determine the surface area of the right square pyramid.

$\large \boxed{\mathfrak{Answer \: with \: Explanation} \downarrow}$

The formula for finding the surface area of a right square pyramid is ⇨ b² + 2bl, where

b = base of the right square pyramid
l = slant height of the right square pyramid.

In the given figure,

base (b) = 4 ft.
slant height (l) = 8 ft.

Now, let's substitute the values of b & l in the formula & solve it :-

$\sf \: {b}^{2} + 2bl \\ = \sf \: {4}^{2} + 2 \times 4 \times 8 \\ = \sf \: 16 + 8 \times 8 \\ = \sf \: 16 + 64 \\ = \huge\boxed{\boxed{ \bf 80 \: ft ^{2} }}$

So, the surface area of the right square pyramid is 80 ft².

7 0

2 years ago