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bearhunter [10]
3 years ago
10

Here is a table of values for y = f(x).

Mathematics
1 answer:
Firlakuza [10]3 years ago
5 0

The true statements are:

B. f(-1) = 6

D. The domain for f(x) is the set {-2 , -1 , 0 , 1 , 2 , 3 , 4 , 5 , 6}

Step-by-step explanation:

The table:

  • →  x  :  -2  :  -1  : 0  :  1  :  2  :  3  :  4  :  5  :  6
  • →  y  :   5  :   6  : 7  :  8 :  9  :  10 :  11 :  12 :  13

∵ y = f(x)

∴ x is the domain of the function

∴ y is the range of the function

Use the table to find them

∵ The values of x are  -2 , -1 , 0 , 1 , 2 , 3 , 4 , 5 , 6

∴ The domain of f(x) is the set {-2 , -1 , 0 , 1 , 2 , 3 , 4 , 5 , 6}

∵ The values of y are 5 , 6 , 7 , 8 , 9 , 10 , 11 , 12 , 13

∴ The range of f(x) is the set {5 , 6 , 7 , 8 , 9 , 10 , 11 , 12 , 13}

∵ f(5) means the value of y at x = 5

∵ The value of y at x = 5 is 12

∴ f(5) = 12

∵ f(-1) means the value of y at x = -1

∵ The value of y at x = -1 is 6

∴ f(-1) = 6

The true statements are:

B. f(-1) = 6

D. The domain for f(x) is the set {-2 , -1 , 0 , 1 , 2 , 3 , 4 , 5 , 6}

Learn more:

You can learn more about the function in brainly.com/question/7128279

#LearnwithBrainly

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3 years ago
Dave has $3000 more in a passbook account than in a money market.
Goryan [66]

The amount in the passbook account is $11,000 and the money in the money market account is $8000

Let:

a represent the unknown amount in the passbook account

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This information can be represented with this equation : a - b = 3000

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a - b = 3000 equation 1

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0.02b = 160

Divide both sides of the equation by 0.02

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2 years ago
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Option fourth "By the addition property of equality, AC² plus AB² = BC multiplied by DC plus AB² is correct.

<h3>What is the Pythagoras theorem?</h3>

The square of the hypotenuse in a right-angled triangle is equal to the sum of the squares of the other two sides.

The figure is missing.

The right-angle triangle is shown in the picture; please refer to the picture.

The missing options are attached; please refer to the picture.

We have a right-angle triangle shown in the picture.

The larger triangle ABC is similar to the smaller triangles as follows.

ΔABC ~ ΔDBA     (By AA similarity)

ΔABC ~ ΔDAC   (By AA similarity)

From the above similarity:

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After cross multiplication:

AB² = BC×BD

Now,

\rm \dfrac{AC}{CD} = \dfrac{BC}{AC}

AC² = BC×BD

AB² + AC² =  BC×BD + BC×BD

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