Question

if a ball is thrown into the air with a velocity of 40 ft s its height in feet after t seconds is given by s(t)=40t-16t2 find the average velocity for the ball during the time[1,2]

Answer 1

Answer with Step-by-step explanation:

We are given that a ball is thrown into the air with velocity

$v=40ft/s$

Height  after t seconds is given by

$s(t)=40t-16t^2$

We have to find the average velocity for the ball during the time [1,2].

We know that average velocity=$\frac{ds}{dt}$

Average velocity=v=$\frac{d(40t-16t^2)}{dt}=40-32t$

Substitute t=1 then we get

Average velocity=$40-32(1)=40-32=8 m/s$

Substitute t=2 then

Average velocity=$40-32(2)=40-64$

Average velocity[/tex]=-24 m/s[/tex]