Answer:
See explanation
Step-by-step explanation:
Assuming the given inequality is 
Then the corresponding linear equation is 
When x=0, we have 
When y=0, we have 
The T-table is:
<u>x | y</u>
0 | 4
6 | 12
We plot this points and draw a solid straight line as shown in the attachment.
Now let us test the origin: (0,0) by plugging x=0 and y=0 into the inequality.
....This is true so we shade the lower half plane as shown in the attachment.
Answer:
4(p+r) = q
Step-by-step explanation:
p = q/4 -r
Add r to each side
p+r = q/4 -r+r
p+r = q/4
Multiply each side by 4
4(p+r) = q/4*4
4(p+r) = q
we can find the answer to this problem by thinking about it logically for a minute:
we know that she assigned "x" homework problems on Monday, so,
x=Monday
we also know that she assigned 13 more problems on Tuesday, so,
13=Tuesday
over the course of the two days she assigned a total of 23 homework problems.
to get the answer of how many problems she assigned on Monday, we have to do the total number of problems she assigned(23) minus the number of problems we know she assigned on Tuesday(13), so,
23-13=10
she assigned 10 problems on Monday.
Answer:
FG=BD
Step-by-step explanation:
hope this helps!!
Answer:
Option A is correct
The function 
has real zeroes at x =-10 and x =-6
Explanation:
Given: The real zeroes or roots are x = -10, and x = -6
To find the quadratic function of degree 2.
where α,β are real roots. ....[1]
Here, α= -10 and β= -6
Sum of the roots:
α+β = -10+(-6) = -10-6 = -16
Product of the roots:
αβ = (-10)(-6)= 60
Substitute these value in equation [1] we have;
Therefore, the quadratic function for the real roots at x =-10 and x =-6 ;
