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pishuonlain [190]
3 years ago
13

Lily has a piece of ribbon that measure 3 yards 4 inches. She cuts the ribbon into 4 equal pieces. What is the length, in inches

, of each piece of ribbon
Mathematics
1 answer:
lidiya [134]3 years ago
4 0

Answer:

28 inches

Step-by-step explanation:

The piece of ribbon that Lily has is 3 yards 4 inches long.

Let us first put this in inches:

1 yard = 36 inches

=> 3 yards = 3 ^ 36 = 108 inches

The length of Lily's ribbon is:

108 + 4 = 112 inches

She cuts the ribbon into 4 equal pieces.

To know the length of each piece, we divide the length of Lily's ribbon by 4:

112 / 4 = 28 inches

Each piece of ribbon is 28 inches long.

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Find the surface area of the square pyramid shown below. (Measurements in picture)
Sloan [31]

Given:

Side length of base = 8

Slant height = 6

To find:

The surface area of the square pyramid.

Solution:

Surface area:

$SA=A+\frac{1}{2} p s

where A is the area of base

p is the perimeter of base

s is the slant height

Area of base (A) = 8 × 8

                           = 64

Perimeter of base(P) = 4 × 8

                                  = 32

Substitute these in the formula:

$SA=64+\frac{1}{2} \times 32 \times 6

$SA=64+96

$SA=160

The surface area of the square pyramid is 160 unit².

8 0
3 years ago
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What is the answer ;_;
leonid [27]

Baily had 36 and Elena had 40

7 0
3 years ago
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If f(x) = 4x + 2, what is the value of f(3)? <br><br> O 8<br> O 14<br> O 45<br> O 66
lutik1710 [3]

Answer:

14

Step-by-step explanation:

5 0
3 years ago
FUNDRAISING A school is raising money by selling calendars for $20 each. Mrs. Hawkins promised a party to whichever of her Engli
____ [38]

Rj, this is the solution to question 19:

• 1st period class sold 60 calendars in total

,

• 2nd period class sold 123 calendars in total

We calculate the average per week, this way:

• 1st period class sold 60/4 = 15 calendars per week

,

• 2nd period class sold 123/4 = 30.75 calendars per week

In consequence the multiplication equation that represents this situation is:

15w + 30.75w = 183, where w is the number of weeks Mrs. Hawkins' classes sold calendars.

This is the solution to question 20:

We already know the average number of calendars that 1st and 2nd period classes sold per week. Now, let's calculate the average for 3nd 4th peiod classes, this way:

• 3rd period class sold 89 calendars in total

,

• 4th period class sold 126 calendars in total

Therefore, the average is:

• 3rd period class sold 89/4 = 22.25 calendars per week

,

• 4th period class sold 126/4 = 31.5 calendars per week

Summarizing, we have:

15 + 30.75 + 22.25 + 31.5 = 99.5 calendars was the average number sold by all her classes in a week.

•

7 0
1 year ago
Which function does not have a vertical asymptote
Gemiola [76]

Answer:

y=\frac{5x}{1+2x^2}

Step-by-step explanation:

Option ~A ~ does ~ not ~ have ~a ~ vertical~ asymptote

<u>--------------------------</u>

Hope it helps...

Have a great day!!

8 0
3 years ago
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