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nasty-shy [4]
3 years ago
10

Five added to 3 times a number is equal to 8 less then 5 times the number

Mathematics
1 answer:
RSB [31]3 years ago
6 0

The answer is C. 3x+5= 5x -8

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PLEASE HELP WITH THIS ONE QUESTION
Nana76 [90]

Answer:

I'm not sure about the factors, but it's reflected over the x axis if they helps narrow it down

3 0
2 years ago
How many real roots does the function
icang [17]

Answer:

Option C is correct i.e. 2.

Step-by-step explanation:

Given the function is f(x) = x² +8x -2.

We can compare it with general quadratic expression i.e. ax² +bx +c.

Then a = 1, b = 8, c = -2.

We can find the number of real root by finding discriminant of the equation ax² +bx +c =0 as follows:-

D = b² -4ac

D = 8² -4*1*-2

D = 64 +8

D = 72.

When D is a positive value, then we have two real roots of the equation.

Hence, option C is correct i.e. 2.

6 0
3 years ago
A student expressed the sum of 2 whole numbers as 5 times (8+3).What are the 2 whole numbers?
Marta_Voda [28]

Well if the two numbers are equal to 5x(8+3).

Lets say that these two numbers are X and Y,

So that would be X + Y = 5(8+3)

which means X + Y = 55

You could write that as a fuctions Y = 55 - X

Now by using the graph you get and the X values of [0,55] ( This means every value from 0 to 55 ), you will get a X and Y value that if you added up together will give you the value of 8(5+33)

An examples for the answers would be

(0,55) (1,54) (2,53) (3,52) (4,51) (5,50) (6,49) ... it goes on until x reaches 55.

8 0
3 years ago
What is the expression in radical form?<br><br> (4x3y2)310
sertanlavr [38]

Given:

Consider the given expression is

(4x^3y^2)^{\frac{3}{10}}

To find:

The radical form of given expression.

Solution:

We have,

(4x^3y^2)^{\frac{3}{10}}=(2^2)^{\frac{3}{10}}(x^3)^{\frac{3}{10}}(y^2)^{\frac{3}{10}}

(4x^3y^2)^{\frac{3}{10}}=(2)^{\frac{6}{10}}(x)^{\frac{9}{10}}(y)^{\frac{6}{10}}

(4x^3y^2)^{\frac{3}{10}}=(2)^{\frac{3}{5}}(x)^{\frac{9}{10}}(y)^{\frac{3}{5}}

(4x^3y^2)^{\frac{3}{10}}=\sqrt[5]{2^3}\sqrt[10]{x^9}\sqrt[5]{y^3}       [\because x^{\frac{1}{n}}=\sqrt[n]{x}]

(4x^3y^2)^{\frac{3}{10}}=\sqrt[5]{8y^3}\sqrt[10]{x^9}       [\because x^{\frac{1}{n}}=\sqrt[n]{x}]

Therefore, the required radical form is \sqrt[5]{8y^3}\sqrt[10]{x^9}.

8 0
3 years ago
Enter your answer and show all the steps that you use to solve this problem in the space provided.
rodikova [14]

Answer:

\boxed{f(x) - g(x) = 2x(2x^{2} + x + 1)}

Step-by-step explanation:

f(x) = 9x³ + 2x² - 5x + 4; g(x)=5x³ -7x + 4

Step 1. Calculate the difference between the functions

(a) Write the two functions, one above the other, in decreasing order of exponents.

ƒ(x) = 9x³ + 2x² - 5x + 4

g(x) = 5x³           - 7x + 4

(b) Create a subtraction problem using the two functions

        ƒ(x) =    9x³ + 2x² - 5x + 4

      -g(x) =  <u>-(5x³           - 7x + 4) </u>

ƒ(x) -g(x)=

(c). Subtract terms with the same exponent of x

        ƒ(x)   =    9x³ + 2x² - 5x + 4

      -g(x)  =   <u>-(5x³          -  7x + 4) </u>

ƒ(x) -g(x) =      4x³ + 2x² + 2x

Step 2. Factor the expression

y = 4x³ + 2x² + 2x

Factor 2x from each term

y = 2x(2x² + x + 1)

\boxed{f(x) - g(x) = 2x(2x^{2} + x + 1)}

5 0
3 years ago
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