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Alex_Xolod [135]

3 years ago

12

Debbie set a goal to run 6 miles. On Monday she ran 2.6 miles and on Tuesday she ran 1.75 miles. How far would Debbie need to ru

n on Wednesday to reach her goal?

1 answer:

Makovka662 [10]3 years ago

7 0

She will need to run 1.65 to reach her go

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If x=-4 and y=6, then xy-3=

Anna11 [10]

Answer:

-12

Step-by-step explanation:

We start with the equation: $xy-3x$

Substitute the variables: $(-4)(6)-3(-4)$

Solve using order of operations (start with multiplication): $(-24)-(-12)$

And then addition/subtration: $(-24)-(-12)=-12$

3 0

3 years ago

10x +y =6 written in slope intercept form

hodyreva [135]

Answer:

y = -10x + 6

Step-by-step explanation:

7 0

3 years ago

Read 2 more answers

Rachel earned $42 for 3 1/2 hours at her job today. How much does Rachel earn per hour?

Firdavs [7]

The answer is $12 an hour because 12 times 3 is 36 and half of 12 is 6 so add 6 to 36 and you get 42.

8 0

3 years ago

Suppose a simple random sample of size nequals36 is obtained from a population with mu equals 74 and sigma equals 6. (a) Descri

OlgaM077 [116]

Part a)

The simple random sample of size n=36 is obtained from a population with

$\mu = 74$

and

$\sigma = 6$

The sampling distribution of the sample means has a mean that is equal to mean of the population the sample has been drawn from.

Therefore the sampling distribution has a mean of

$\mu = 74$

The standard error of the means becomes the standard deviation of the sampling distribution.

$\sigma_ { \bar X } = \frac{ \sigma}{ \sqrt{n} } \\ \sigma_ { \bar X } = \frac{ 6}{ \sqrt{36} } = 1$

Part b) We want to find

$P(\bar X \:>\:75.9)$

We need to convert to z-score.

$P(\bar X \:>\:75.9) = P(z \:>\: \frac{75.9 - 74}{1} ) \\ = P(z \:>\: \frac{75.9 - 74}{1} ) \\ = P(z \:>\: 1.9) \\ = 0.0287$

Part c)

We want to find

$P(\bar X \: < \:71.95)$

We convert to z-score and use the normal distribution table to find the corresponding area.

$P(\bar X \: < \:71.95) = P(z \: < \: \frac{71.9 5- 74}{1} ) \\ = P(z \: < \: \frac{71.9 5- 74}{1} ) \\ = P(z \: < \: - 2.05) \\ = 0.0202$

Part d)

We want to find :

$P(73\:$

We convert to z-scores and again use the standard normal distribution table.

$P( \frac{73 - 74}{1} \:< \: z$

5 0

2 years ago

I’m not very sure how to simplify the two bottom rows, can someone help me?

love history [14]

Answer:

The simplification is done below.

Step-by-step explanation:

$(\sin(\frac{\pi}{6})\cos(\frac{\pi}{4}) - \sin(\frac{\pi}{4})\cos(\frac{\pi}{6}))^{2}$

= $(\frac{1}{2} \times \frac{1}{\sqrt{2}} - \frac{1}{\sqrt{2}} \times \frac{\sqrt{3}}{2})^{2}$

= $((\frac{1}{2\sqrt{2}}) \times (1 - \sqrt{3}))^{2}$

= $0.125 \times (1 - (2 \times \sqrt{3}) +3)$

5 0

2 years ago