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3 years ago

Plz answer as soon as possible

Mathematics

1 answer:

Mamont248 [21]3 years ago

3 0

THE FIRST ONE AND THE LAST ONE

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The sample consisted of 50 night students, with a sample mean GPA of 3.02 and a standard deviation of 0.08, and 25 day students,

bulgar [2K]

Answer: The test statistic is t= -0.90.

Step-by-step explanation:

Since we have given that

n₁ = 50

n₂ = 25

$\bar{x_1}=3.02\\\\\bar{x_2}=3.04\\\\\sigma_1=0.08\\\\\sigma_2=0.06$

So, s would be

$s=\sqrt{\dfrac{n_1\sigma_1^2+n_2\sigma_2^2}{n_1+n_2-2}}\\\\s=\sqrt{\dfrac{50\times 0.08^2+25\times 0.06^2}{50+25-2}}\\\\s=0.075$

So, the value of test statistic would be

$t=\dfrac{\bar{x_1}-\bar{x_2}}{s(\dfrac{1}{n_1}+\dfrac{1}{n_2})}\\t=\dfrac{3.02-3.04}{0.074(\dfrac{1}{50}+\dfrac{1}{25})}\\\\t=\dfrac{-0.04}{0.074(0.02+0.04)}\\\\t=\dfrac{-0.04}{0.044}\\\\t=-0.90$

Hence, the test statistic is t= -0.90.

7 0

3 years ago

What is the answer for this question??? i need it

JulijaS [17]

Answer:

f(4)=14

Step-by-step explanation:

a) u do it by substituting 4 in places where there r 'x'

since this one say f(4) it only can go to the function which says f(x)
f(x)=4x-2
f(4)=4(4)-2, so according to BODMAS rule multiplication comes first rather than subtraction

so, f(4)=16-2=14
f(4)=14
do the others based on this, hope i explained well, if i did, please gimme brainliest :)

4 0

2 years ago

What is the product of 9 and -7?

kolezko [41]

Answer:

The product of 9 and -7 is -63

Step-by-step explanation:

Hope This Helped!

3 0

3 years ago

In the circle below, EG is a diameter and EF is tangent at E. Suppose mEF = 124°. Find the following. Does anyone know this?

Ludmilka [50]

Answer:

Step-by-step explanation:

If EG is a diameter, then arc EFG is a semicircle and its measure is 180. Arc FG then is 180 - 124 = 56. Since angle FEG is an inscribed angle and the arc it cuts off is arc FG, then the measure of the inscribed angle is half the measure of the arc it cuts off...so angle FEG is 28 degrees. Keep that in mind; we'll need it in a sec.

If HE is tangent to the circle at E, then angle HEG is a 90 degree angle. Adding that to angle FEG will give you angle FEH. Angle FEH = 90 + 28 = 118

8 0

3 years ago

PQRS has vertices P(0, 0), Q(4, 2), and S(4, ␣2). Its diagonals intersect at H(4, 0). What are the possible coordinates of R for

True [87]

Any point on the x-axis beyond the point (4, 0) is a possible cordinate of R.

8 0

3 years ago