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lesantik [10]
3 years ago
14

You are given four test tubes, each containing an unknown protist, and your task is to read the following description and match

these four protists to the correct test tube. When light, especially red and blue light, is shone on the tubes, oxygen bubbles accumulate on the inside of test tubes 1 and 2. Chemical analysis of test tube 1 indicates the presence of a chemical that is toxic to fish and humans. Chemical analysis of test tube 2 indicates the presence of substantial amounts of silica. Microscopic analysis of organisms in test tubes 1, 3, and 4 reveals the presence of permanent, membrane-bounded sacs just under the plasma membrane. Microscopic analysis of organisms in test tube 3 reveals the presence of an apicoplast in each. Microscopic analysis of the contents in test tube 4 reveals the presence of one large nucleus and one small nucleus in each organism. Test tube 3 contains ________.
Biology
1 answer:
zepelin [54]3 years ago
3 0

Answer:

Plasmodium

Explanation:

in tube 3, you can see the apicoplast which is actually a derived non-photosynthetic plastid which are important for the growth and survival of malarial parasites which belong to genus Plasmodium.

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—Explanation—
•] The definition of limiting factor; anything that constrains a population's size and slows or stops it from growing.
•]Some examples of limiting factors are biotic, like food, mates, and competition with other organisms for resources.
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4. A polypeptide has the following amino acid sequence: Met-Ser-Pro-Arg-Leu-Glu-Gly In the mutant below, indicate the type of mu
MatroZZZ [7]

Answer:

4. c. Deletion/ frameshift mutation

5. a. Tyr Tyr Asp Ser Gly

6. A frameshift occurred which altered the identity of the amino acids following the initiator 6. methionine, but not the length of protein Q.

Explanation:

4)

A single base pair at the first position of the Arg codon i.e. CGA has been deleted. Due to the deletion, the reading frame has shifted one nucleotide backwards, altering the amino acid sequence of the protein.

5)

The genomic DNA sequence is 5'-ATG ATA CTA AGG CCC-3'. Therefore, the complementary mRNA will be 5'-UAC UAU GAU UCC GGG-3'. According to the genetic code, this mRNA sequence encodes the following amino acid sequence: Tyr Tyr Asp Ser Gly

6)

The wild type DNA sequence is:

5'-ACUGUAAUGGAGUCAGAUGAUGCAUUAAGGAGAAAUUGAAAUAAA-3'

The mutant i.e. mRNA with the added G will be

5' ACUGUAAUGGGAGUCAGAUGAUGCAUUAAGGAGAAAUUGAAAUAAA-3'  

This is a single base pair insertion and frameshift mutation that shifts the reading frame one base pair forwards. The codon that was originally GAG coding for glutamic acid (Glu) gets converted to GGA that codes for glycine. Therefore, the amino acid sequence has been altered but the polypeptide chain will still have 13 amino acids.

6 0
3 years ago
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100% all offspring will be Ee - showing the dominant trait - detached earlobes
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