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lesantik [10]
3 years ago
14

You are given four test tubes, each containing an unknown protist, and your task is to read the following description and match

these four protists to the correct test tube. When light, especially red and blue light, is shone on the tubes, oxygen bubbles accumulate on the inside of test tubes 1 and 2. Chemical analysis of test tube 1 indicates the presence of a chemical that is toxic to fish and humans. Chemical analysis of test tube 2 indicates the presence of substantial amounts of silica. Microscopic analysis of organisms in test tubes 1, 3, and 4 reveals the presence of permanent, membrane-bounded sacs just under the plasma membrane. Microscopic analysis of organisms in test tube 3 reveals the presence of an apicoplast in each. Microscopic analysis of the contents in test tube 4 reveals the presence of one large nucleus and one small nucleus in each organism. Test tube 3 contains ________.
Biology
1 answer:
zepelin [54]3 years ago
3 0

Answer:

Plasmodium

Explanation:

in tube 3, you can see the apicoplast which is actually a derived non-photosynthetic plastid which are important for the growth and survival of malarial parasites which belong to genus Plasmodium.

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30% of B-A=18% OF B+A <br>THEN A:B?
dlinn [17]

Answer:

1:4

Explanation:

30%= \frac{30}{100}

18%= \frac{18}{100}

<em>Rewrite the given information:</em>

\frac{30}{100} (B - A) =  \frac{18}{100}(B + A)

<em>Multiply by 100 throughout:</em>

30(B -A)= 18(B+A)

<em>Divide by 6 throughout,</em>

5(B -A)= 3(B +A)

<em>Expand</em>

5B -5A= 3B +3A

<em>Bring</em><em> </em><em>A</em><em> </em><em>terms</em><em> </em><em>to</em><em> </em><em>1</em><em> </em><em>side</em><em> </em><em>and</em><em> </em><em>B</em><em> </em><em>terms</em><em> </em><em>to</em><em> </em><em>another</em><em>:</em>

5B -3B= 5A +3A

<em>Simplify</em>

2B= 8A

<em>Divide by 2 throughout:</em>

B= 4A

Now, we have to find the ratio of A to B.

B= 4A

<em>Divide by 4 throughout:</em>

A = =  \frac{1}{4} B

<em>Divide by B on both sides:</em>

\frac{A}{B}  =  \frac{1}{4}

Thus, A:B= 1:4

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outside of the cell do to the concentration gradient

Explanation:

8 0
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