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ella [17]
3 years ago
10

Does this sentence from The Savoy move at a fast pace or a slow pace?

English
1 answer:
miv72 [106K]3 years ago
5 0
I would say fast because it feels like it’s tension in the phrase
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Add adjectives to create sensory details<br><br> The distant __________ of ___________
maksim [4K]

Answer:

The distant yummy smell of tasteful meat.

Explanation:

I think this would be correct.

Hope I helped you

3 0
2 years ago
20 POINTS
krek1111 [17]

The answer for this question is C: an exiting celebration.


I hope this helped~!

4 0
3 years ago
Read 2 more answers
1. Prepare a dialogue between two friends about the importance of library in school.(5)​
alexandr402 [8]

Answer:

A: oh hello!

Q: I'm glad to see you're still working at the library

A: oh me too!

Q: Why do you work here? Are there other good places?

A: That's because libraries are useful for people. It's worth it, with great equipment!

Q: Yes, also, there are many books with lots of useful information for students.

A: I want to help students find the information they need faster, so here I am! When working at the library, I feel happy when the students are always studying hard, borrowing books and studying quietly.

Q: I know we both work really hard and it's not easy, but you have to keep going! Try hard!

A: Wherever you go, be sure to visit here every Sunday. We send our love and miss you.

Q: hey, thanks...

good luck!

3 0
2 years ago
I will make you brainlist if you help me the 2 question by explain them i swear i will make you brainlist
Xelga [282]

★ Formula Applied :

\begin{gathered}\sf \bullet\ \; cos^2x-sin^2x=cos2x\\\\\to\ \sf \pink{sin^2x-cos^2x=-cos2x}\end{gathered}

\begin{gathered}\bullet\ \; \sf sin2x=2.sinx.cosx\\\\\to \sf \blue{sinx.cosx=\dfrac{sin2x}{2}}\end{gathered}

\displaystyle \bullet\ \; \sf \int \dfrac{dx}{x}

\bullet\ \; \sf \ln (ab)=\ln a+\ln

★ Explanation :

\begin{gathered}\displaystyle \sf \int \dfrac{sin^2x-cos^2x}{sinx.cosx}dx\\\\\to \sf \int \dfrac{-cos2x}{\frac{sin2x}{2}}dx\\\\\to \sf \int \dfrac{-2cos2x}{sin2x}dx\end{gathered}

Lets use substitution method ,

Let , u = sin2x

⇒ du = 2.cos2x.dx

\begin{gathered}\to \displaystyle \sf \int \dfrac{-du}{u}\\\\\to \sf -\int \dfrac{du}{u}\\\\\to \sf -ln|u|\\\\\end{gathered}

\to \sf \red{-ln|sin2x|+c}

\to \sf - \ln |2sinx.cosx|+c

\to \sf - \ln |sinx.cosx|+(\ln 2+c)

\leadsto - \sf \red{\ln |sinx.cosx|+c}\ \; \bigstar

★ Alternate Method :

\displaystyle \sf \int \dfrac{sin^2x-cos^2x}{sinx.cosx}

\displaystyle \to \sf \int \left( \dfrac{sin^2x}{sinx.cosx}-\dfrac{cos^2x}{sinx.cosx}\right)dx

\begin{gathered}\displaystyle \to \sf \int \left( \dfrac{sinx}{cosx} -\dfrac{cosx}{sinx} \right)dx\\\\\to\ \sf \int (tanx-cotx)dx\\\\\to \sf \int tanx.dx-\int cotx.dx\\\\\to \sf ln|secx|-ln|sinx|+c\end{gathered}

\to \sf ln\left| \dfrac{secx}{sinx}\right|+c

\begin{gathered}\to \sf ln\left| \dfrac{1}{sinx.cosx} \right|+c\\\\\end{gathered}]

\leadsto \sf \pink{-ln|sinx.cosx|+c}\ \; \bigstar

4 0
2 years ago
What was Hamer's goal?
mamaluj [8]

Answer:

Hamer worked to help the poor and families in need in her Mississippi community. She also set up organizations to increase business opportunities for minorities and to provide childcare

Explanation:

8 0
3 years ago
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