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Travka [436]
3 years ago
14

What is an equation, in standard form, of the line through (1, 7) and (-2, -3)?

Mathematics
1 answer:
stellarik [79]3 years ago
4 0

Answer:

y= 1/3x + 3.66

Step-by-step explanation:

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A father’s age is the square of his son’s age (x). In 20 years’ time the father will be 3 times as old as his son. What are the
VMariaS [17]

If the current son's age is x, the current age of the father is x^2.

In 20 years they will be, respectively, x+20 and x^2+20 years old, and we know that the father will be 3 times as old as his son:

x^2+20=3(x+20) \iff x^2+20=3x+60 \iff x^2-3x-40=0

The quadratic equation has solutions

x_{1,2}=\dfrac{3\pm\sqrt{9+160}}{2}=\dfrac{3\pm 13}{2}

So, the two solutions are

x_1 = \dfrac{16}{2}=8,\quad x_2 = \dfrac{-10}{2}=-5

We clearly can't accept negative values as solution for a problem involving the age of a person, so the only feasible solution is x=8, and we deduce that the father's age is 8 squared, i.e. 64.

6 0
3 years ago
Need help answering question 4
raketka [301]

Answer:

(-1,5)

Step-by-step explanation:

To find this, you have to add both "x" coordinates, then divide them by two.

Same thing goes for the "y" coordinates, add them, then divide them by two.

x-coordinates --->  2+(-4)= -2

y-coordinates ---> 1+9= 10

-2÷2= -1

10÷2= 5

That gives you, (-1,5).

4 0
3 years ago
Select the correct answer.
Ilia_Sergeevich [38]

Answer:b

Step-by-step explanation:

6 0
3 years ago
Read 2 more answers
GIVING BRAINLIEST! IM BEGGING YOU PLEASE HELP ME THIS IS DUE TODAY AND I NEED TO HELP MY FRIEND! I CANT HELP THEM UNTIL I FINISH
RSB [31]

Here are the answers

C) 118

D) 64

A) pi(d)

B) ST

A) 22, 61, 97

8 0
3 years ago
Read 2 more answers
What are the solutions of the system 7x + 3y=-3 and y= -2*?
mafiozo [28]

Answer:

opt 4

Step-by-step explanation:

when x=0, 0+3y= -3, so y=-1    (0,-1) is solution

         when x=3 , 21+3y=-3,  3y= -3-21= -24

                                                    y= -8                  (3,-8) is also solution

8 0
3 years ago
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