Answer:
The correct conversion is B)
B) 200km 1hr x 1000m 1km x 1hr 60min x 1min 60s
Hence,
200 km/h ⇒ 
Step-by-step explanation:
Given:
An airplane is traveling at a speed of 200 km/h.
The correct conversion is B)
B) 200km 1hr x 1000m 1km x 1hr 60min x 1min 60s
Reason:
For Converting Speed unit km/h ⇒ m/s
First we need to convert km ⇒ meter
So 1 km = 1000 meter
Secondly, in hour ⇒ seconds first we need to convert it into minutes then to seconds
hour ⇒ minute ⇒ seconds
So 1 hour = 60 minute and 1 minute = 60 seconds
Therefore, 1 hour = 60 min × 60 sec
Hence,
200 km/h ⇒
You can use cross multiplication here. This is where we multiply the bottoms of the factions with the tops of the other one.
9 moves over to the lop left and 12 to the top right to give
12(4x-15)=9(5x+6)
48x-180=45x+54
3x=234
x=78
Answer:
A.Swing two arcs above and below the radius.
Step-by-step explanation:
The statement in option A is not used in constructing an inscribed hexagon. While constructing a inscribed hexagon, swinging of the arcs is done on only one direction to cut the circumference of the circle.
Steps of constructing an inscribed hexagon are :
1. Draw a circle on a paper with the help of a compass.
2. Mark a point on the circumference of the circle and make it a starting point.
3. Now with the same span on the compass, place the compass pointer on the previous point on the circumference and swing a small arc cutting the circumference.
4. Now with same span, place the compass pointer on the intersecting point of the small arc and the circumference and make second small arc on the circumference.
5. Continue making arcs on the circumference until we reach the 1st point.
6. Now join the intersecting points on the circle and make a hexagon.
So it i clear from the above that swinging two arcs below and above the radius is not required. Thus option A is not required.
Yes it is Direct Variation. Y/X=8
*X *X
Y=8X
Given
Height (length) of the anchor dropped from the boat = 75 feet
Distance of the treasure from the anchor = 40 feet
Solution
The dropped at the bottom makes an angle of 90 degree . Therefore making an right triangle with the chest and boat
By Pythagoras theorem
AC^2 = AB^2 + BC^2
(AC = distance of the treasure from the boat
AB = height of the anchor dropped from the boat
BC = the distance of treasure from the anchor)
AC^2 = 75^2 + 40^2
AC^2 = 5325 +1600
AC^2 = 6925
AC = 25 * (under root 11)
Therefore they have cover a distance of 25 * (under root 11)
