Gracie, Mary, and Nancy each have a small collection of seashells. Gracie has 5 more than times the number of shells Mary has. N

Question

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Gracie, Mary, and Nancy each have a small collection of seashells. Gracie has 5 more than times the number of shells Mary has. N

ancy has 1 more than times the number of shells Mary has. Gracie and Nancy have the same number of shells. If x is the number of shells Mary has, identify the equation that represents this situation and identify its solution.

Mathematics

2 answers:

Zielflug [23.3K] · Answer 1 · 2022-08-25T20:12:13+03:00

Answer:

3/2 x +1 = 5/4x - 5

3/2 x+1 =5/4

x−5

Step 1: Subtract 5/4x from both sides.

3/2 x+1−5/4

x=5

4x−5−5/4x

1/4x+1=−5

Step 2: Subtract 1 from both sides.

1/4x+1−1=−5−1

1/4

x=−6

Step 3: Multiply both sides by 4.

4*(1/4x)=(4)*(−6)

x=−24 Mary has 24 shells

Answer:

-x=−24

x = 24 shells

Step-by-step explanation:

1. 2 3/4 x 16 = 44 + 6 = 50 shells x= 16

2 3/4 x 24 = 66 + 6 = 72 x = 24

We see the side workings in bold as if Mary has 24 and Nancy has 1x more

Then Nancy 24+24 = 48 where Gracie 5 x 24 = 120 and we have 72-48 = 24 and 120-72 = 48 being the same as Nancy. You can ignore or check the rest in explanation.

2 3/4 x 18 = 49 1/2 + 6 = 55 1/2 x= 18

2. 2 3/4 x 16 = 44 -4 = 40 shells x = 16 2 3/4 x 24 = 66 - 4 = 62 x = 24

2 3/4 x 18 = 49 1/2 - 4 = 45 1/2 x = 18

3. 2 3/4 x 16 = 44 + 4 = 48 shells x = 16 2 3/4 x 24 = 66 + 4 = 70 x = 24

2 3/4 x 18 = 49 1/2 + 4 =53 1/2 x = 18