Y=2(x-3)^2 +7 would be the way to rewrite this equation in vertex form.
Answer:
The graph in the attached figure
Step-by-step explanation:
we have

This is a linear equation (the graph is a line)
To identify the graph find out the intercepts
<u><em>Find out the y-intercept</em></u>
The y-intercept is the value of y when the value of x is equal to zero
For x=0

The y-intercept is the point (0,-4)
<u><em>Find out the x-intercept</em></u>
The x-intercept is the value of x when the value of y is equal to zero
For y=0



The x-intercept is the point (5.33,0)
therefore
The graph in the attached figure
Answer:324
Step-by-step explanation:
int i = 42.7; /* konwersja z double do int */
float f = i; /* konwersja z int do float */
double d = f; /* konwersja z float do double */
unsigned u = i; /* konwersja z int do unsigned int */
f = 4.2; /* konwersja z double do float */
i = d; /* konwersja z double do int */
char *str = "foo"; /* konwersja z const char* do char* [1] */
const char *cstr = str; /* konwersja z char* do const char* */
void *ptr = str; /* konwersja z char* do void* */
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