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Makovka662 [10]
2 years ago
5

|60| ___ |-60| is it greater than > equal to = or less than

Mathematics
2 answers:
o-na [289]2 years ago
5 0

Answer:

|60|  =  | - 60|

Step-by-step explanation:

They are equal. When the negative sign is inside the box the absolute value is positive, when the negative sign is outside the box THEN it is negative.

olasank [31]2 years ago
5 0

Answer: equal to

Step-by-step explanation: Absolute value means <em>distance from zero</em> on a number line. To represent the absolute value of a number, we use a vertical bar on either side of the number like we see in this problem.

So for the absolute value of 60, we know that 60 is 60 units from zero on a number line which means that the absolute value of 60 is just 60.

For the absolute value of -60, we know that -60 is also 60 units from zero on the number line so the absolute value of -60 is also 60.

Now we know that the absolute value of -60 is 60 and the absolute value of 60 is also 60. Since 60 is the same as 60, it means that 60 <em>is equal to</em> 60.

Another way of thinking about absolute value is that no matter what number you have inside the absolute value, your result will always be positive except for 0 which has an absolute value of 0.

In other words, the absolute value of any number is the positive version of that number. Again, not including zero.

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the area of a gymnasium floor is 264 square yard. the floor is 11 yards wide . how long is the floor?
Alekssandra [29.7K]
Area = Length x Width (A = L x W)

A = 264, W = 11, L = ?

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Find the area under the standard normal probability distribution between the following pairs of​ z-scores. a. z=0 and z=3.00 e.
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Answer:

a. P(0 < z < 3.00) =  0.4987

b. P(0 < z < 1.00) =  0.3414

c. P(0 < z < 2.00) = 0.4773

d. P(0 < z < 0.79) = 0.2852

e. P(-3.00 < z < 0) = 0.4987

f. P(-1.00 < z < 0) = 0.3414

g. P(-1.58 < z < 0) = 0.4429

h. P(-0.79 < z < 0) = 0.2852

Step-by-step explanation:

Find the area under the standard normal probability distribution between the following pairs of​ z-scores.

a. z=0 and z=3.00

From the standard normal distribution tables,

P(Z< 0) = 0.5  and P (Z< 3.00) = 0.9987

Thus;

P(0 < z < 3.00) = 0.9987 - 0.5

P(0 < z < 3.00) =  0.4987

b. b. z=0 and z=1.00

From the standard normal distribution tables,

P(Z< 0) = 0.5  and P (Z< 1.00) = 0.8414

Thus;

P(0 < z < 1.00) = 0.8414 - 0.5

P(0 < z < 1.00) =  0.3414

c. z=0 and z=2.00

From the standard normal distribution tables,

P(Z< 0) = 0.5  and P (Z< 2.00) = 0.9773

Thus;

P(0 < z < 2.00) = 0.9773 - 0.5

P(0 < z < 2.00) = 0.4773

d.  z=0 and z=0.79

From the standard normal distribution tables,

P(Z< 0) = 0.5  and P (Z< 0.79) = 0.7852

Thus;

P(0 < z < 0.79) = 0.7852- 0.5

P(0 < z < 0.79) = 0.2852

e. z=−3.00 and z=0

From the standard normal distribution tables,

P(Z< -3.00) = 0.0014  and P(Z< 0) = 0.5

Thus;

P(-3.00 < z < 0 ) = 0.5 - 0.0013

P(-3.00 < z < 0) = 0.4987

f. z=−1.00 and z=0

From the standard normal distribution tables,

P(Z< -1.00) = 0.1587  and P(Z< 0) = 0.5

Thus;

P(-1.00 < z < 0 ) = 0.5 -  0.1586

P(-1.00 < z < 0) = 0.3414

g. z=−1.58 and z=0

From the standard normal distribution tables,

P(Z< -1.58) = 0.0571  and P(Z< 0) = 0.5

Thus;

P(-1.58 < z < 0 ) = 0.5 -  0.0571

P(-1.58 < z < 0) = 0.4429

h. z=−0.79 and z=0

From the standard normal distribution tables,

P(Z< -0.79) = 0.2148  and P(Z< 0) = 0.5

Thus;

P(-0.79 < z < 0 ) = 0.5 -  0.2148

P(-0.79 < z < 0) = 0.2852

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Answer:

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Answer:

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Step-by-step explanation:

156 times 1° is 156°.

In radians, the angle measure is (156°)(π/180°) = 13π/15 radians.

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