2 years ago

What is the sum of the prime factors of the number 330?

Mathematics

1 answer:

Elena L [17]2 years ago

3 0

Answer:

Step-by-step explanation:

prim factors: 2, 3, 5, and 11

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3x3-27x=0<br> Solve by factoring a

Eddi Din [679]

After factoring $3x^3-27x=0$ the solutions are x=0 , x=3, x= -3

Step-by-step explanation:

We need to solve by factoring:

$3x^3-27x=0$

Solving:

$3x^3-27x=0$

Taking 3x common:

$3x(x^2-9)=0$

Now using formula $a^2-b^2=(a-b)(a+b)$

$3x((x)^2-(3)^2)=0\\3x(x-3)(x+3)=0$

$3x=0\,\,and\,\,x+3=0\,\,and\,\,x-3=0\\x=0\,\,and\,\,x=-3\,\,and\,\,x=3\\$

So, After factoring $3x^3-27x=0$ the solutions are x=0 , x=3, x= -3

Keywords: Factorization

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