All categories

3 years ago

Dance lessons cost $198.75 for 15 classes

Mathematics

1 answer:

zysi [14]3 years ago

6 0

Answer:

331.25

Step-by-step explanation:

First you want to find how much each class cost. So first you want to divide $198.75 by 15 and you will get 13.25. Once you do that you will multiply 13.25 by 25 to get 331.25. Your welcome.

You might be interested in

In the figure, mAB = 45° and mCD = 23°. The diagram is not drawn to scale.

Yakvenalex [24]

Answer:

Option A. $x=34\°$

Step-by-step explanation:

we know that

The measure of the inner angle is the semi-sum of the arcs comprising it and its opposite.

$x=\frac{1}{2}(arc\ CD+arc\ AB)$

substitute the values

$x=\frac{1}{2}(23\°+45\°)$

$x=34\°$

4 0

3 years ago

in the figure below trianglePQM and triangleQRP are right triangles. the measure of lineQM is 6 and the measure of lineQP is 8.

Kipish [7]

Answer:

Option 4 is correct. The length of PR is 6.4 units.

Step-by-step explanation:

From the given figure it is noticed that the triangle PQR and triangle MQR.

Let the length of PR be x.

Pythagoras formula

$hypotenuse^2=base^2+perpendicular^2$

Use pythagoras formula for triangle PQM.

$PM^2=QM^2+PQ^2$

$PM^2=(6)^2+(8)^2$

$PM^2=36+64$

$PM^2=100$

$PM=10$

The value of PM is 10. The length of PR is x, so the length of MR is (10-x).

Use pythagoras formula for triangle PQR.

$PQ^2=QR^2+PR^2$

$(8)^2=QR^2+x^2$

$64-x^2=QR^2$ .....(1)

Use pythagoras formula for triangle MQR.

$MQ^2=QR^2+MR^2$

$(6)^2=QR^2+(10-x)^2$

$36=QR^2+x^2-20x+100$

$36-x^2+20x-100=QR^2$ .... (2)

From equation (1) and (2) we get

$36-x^2+20x-100=64-x^2$

$20x-64=64$

$20x=128$

$x=6.4$

Therefore length of PR is 6.4 units and option 4 is correct.

3 0

3 years ago

What is the answer I need help ASAP

ira [324]

Answer:

C) 4

Step-by-step explanation:

5 0

3 years ago

If LM = 6, what is the perimeter of △PKQ?

vovangra [49]

Answer:

KM=LN Given

KM=KL+LM Segment Addition Postulate

LN=LM+MN Segment Addition Postulate

KL+LM=LM+MN Substitution Property of Equality

KL=MN Subtraction Property of Equality this is the formula :)

Step-by-step explanation:

7 0

3 years ago

Read 2 more answers

g Two different factories named A and B both produce an automobile part. If a part came from A, the probability that the part is

Fed [463]

Answer:

0.0444 = 4.44% probability that a part chosen at random (from the sample) was defective.

Step-by-step explanation:

Probability of a defective part:

0.04 of $\frac{100}{180}$ , that is, coming from A.

0.05 of $\frac{80}{180}$ , that is, coming from B. So

$p = 0.04\frac{100}{180} + 0.05\frac{80}{180} = \frac{0.04*100 + 0.05*80}{180} = 0.0444$

0.0444 = 4.44% probability that a part chosen at random (from the sample) was defective.

3 0

3 years ago