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Anna007 [38]
3 years ago
6

The set of ordered pairs shown represents a function, f,

Mathematics
2 answers:
Rus_ich [418]3 years ago
4 0

Answer:

B) (4, 0)

C) (0, -1)

E) (2, 3)

Step-by-step explanation:

If we see the rule of function then it says that,

a function is a special relationship where each input, x,  has a single output, y.

It means that for every value of x there SHOULD be a different value of y.

A)

(-3,-2) Rejected

because when x = 3, y = -2  

D)

(1, 6) Rejected

because when x = 0, y = 6  

F)

(-5, 9) Rejected

because when x = 4, y = 9  

Step2247 [10]3 years ago
4 0

Answer:

The correct options are A, D and E.

Step-by-step explanation:

The given set of ordered pairs represents a function

f=\{(-5, 3), (4, 9), (3, -2), (0, 6)\}

We need to find THREE ordered pairs that could be added to the set that would allow f to remain a function.

A relation is a function if there exist unique value of y for each value of x.

The x values for given function are -5, 4, 3 and 0.

If we add (-3,-2) in the given set, then we unique value of y for each value of x.  So, option A is correct.

If we add (4,0) in the given set, then we have y=0 and y=9 at x=4. Since the set have more than one value of y for same x-value, therefore option B is incorrect.

If we add (0,-1) in the given set, then we have y=-1 and y=6 at x=0. Since the set have more than one value of y for same x-value, therefore option C is incorrect.

If we add (1,6) in the given set, then we unique value of y for each value of x.  So, option D is correct.

If we add (2,3) in the given set, then we unique value of y for each value of x.  So, option E is correct.

If we add (-5,9) in the given set, then we have y=9 and y=3 at x=-5. Since the set have more than one value of y for same x-value, therefore option F is incorrect.

Therefore the correct options are A, D and E.

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Hi can you please help me with my work
xenn [34]
A, D, and E are true

One X on the line plot marks one time something happened. So the two x’s above the 1 means that he practiced piano for one hour (see to the right that says hours next to the numbers, so 1=1 hour) two times.

45 minutes is 3/4 of an hour, and is the mark right between 1/2 and 1. There is one x above this mark, so that means Thaddeus practiced for 45 minutes one time, so B is false

Thadeus practiced piano for 30 minutes two times, so C is false because he didn’t mostly practice for thirty minutes.

D is correct because there are 2 Xs above the 0, which means two times he practiced for zero hours, which means he didn’t practice at all.

E is correct because 15 minutes is 1/4 of an hour, so it is the mark between 0 and 1/2. We see there are three x’s there, so that means he practiced for 15 minutes 3 times.

I hope this helps! Let me know if you want me to explain it differently.
4 0
3 years ago
Please help meeeeee with this
aleksandrvk [35]
Alright, let's do all of these (though this is a bit long).
1.
The constant is 1.8. All other values are coefficients to variables, which as the name implies will change.
2.
1 hour is 60 minutes, 1 minute is 60 seconds.
So, 4.2 *60 *60 = 15120 seconds.
3.
<span>−5x−4(x−6)=−3-5x-4(x-6)=-3
Let's move all x to one side, and all other numbers to another.
-5x-4(x-6)=-3-5x-4(x-6)=-3
x can be any value you want, if you actually solve this you'll only end up with -3 = -3, which is correct, of course.
Let me show you:
</span><span>−5x−4(x−6)=−3-5x-4(x-6)=-3
+5x +4(x-6)        +5x +4(x-6)
-3 = -3
The value of x is irrelevant, then. X can be any real number.
4.
I'm going to assume it was an error in printing with this? If not please correct me.
m=a+2b(or b2)
subtract 2b from each
a=m-2b
(This question seems kind of odd. We should probably address this in the comments.)
5.
</span><span>5(x−2)<−3x+6
Move all x to one side, numbers to other.
5x-10<-3x+6
+3x     +3x
    +10      +10
8x<16
/8
<span>x < 2
</span>6.
y-3=3(x-5)
alright, to find zeros set one variable to zero and solve
x first
-3=3x-15
+15    +15
3x=12
/3
x=4
x-int is (4,0)
now y
</span>y-3=3(0-5)
y-3=-15
+3     +3
y=-12
so y-int is (0,-12)
i've got to sleep now so i'll do the rest tomorrow. Sorry for the incomplete answer.

8 0
3 years ago
NEEEEEEDDDDD HELP ASAP
mash [69]
The correct answer is that there is more variability in the heights of the volleyball team members.

The mean absolute deviation shows us how spread out the data is, so the larger the mean absolute deviation the higher the variability.

Both teams have players that are 76 inches tall, so the last two statements cannot be true.
6 0
3 years ago
50,000 contestants participate in an on-line game. The game randomly eliminates 20% of the contestants each day. Determine the n
irga5000 [103]

Answer:10,486 contestants

Step-by-step explanation:

First day:

Total number of contestants at the beginning = 50,000

After first day, 20% 0f 50,000 are removed.

That is, (20/100)×50,000 = 10,000

Contestants remaining after first day = 50,000-10,000 = 40,000

Second day:

Contestants= 40,000

20% removed

That is (20/100)×40000=8000

Balance =40000-8000=32,000

Third day:

Contestants= 32000

20% removed

That is (20/100)×32000=6400

Balance =32000-6400=25,600

Fouth day:

Contestants= 25,600

20% removed

That is (20/100)×25,600=5,120

Balance =25,600-5,120=20,480

Fifth day:

Contestants= 20,480

20% removed

That is (20/100)×20,480=4096

Balance =20,480-4096=16,384

Sixth day:

Contestants= 16,384

20% removed

That is (20/100)×16,384=3276.8

Balance =16,384-3276.8=13,107.2

Seventh day:

Contestants= 13,107.2

20% removed

That is (20/100)×13,107.2=2621.44

Balance =13107.2-2621.44=10485.76

Therefore, number of contestants remaining after one week equals 10,486.

6 0
3 years ago
Simplify the expression 11+2/3(15-21a)
Delvig [45]

Answer:

21-14a

Step-by-step explanation:

You have to distribute the (2/3) into the (15-21a) then add it to the 11.  So after distributing the (2/3) into the (15-21a) is (10-14a).  Then add that to the 11

7 0
3 years ago
Read 2 more answers
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