let's find the area of the outer circle and the inside circle
the inside's circle area
A= π x 6²=36π
the outer's
A' = π x 4x²= 4πx²
A'-A=4πx²- 36π=160πcm² equivalent to x²- 9=40, so x²=49 implies x =sqrt(49)=7, x=7.
Answer:
Area of triangle is 9.88 units^2
Step-by-step explanation:
We need to find the area of triangle
Given E(5,1), F(0,4), D(0,8)
We will use formula:

We need to find the lengths of side DE, EF and FD
Length of side DE = a = 
Length of side DE = a = 
Length of side EF = b = 
Length of side EF = b = 
Length of side FD = c = 
Length of side FD = c = 
so, a= 8.60, b= 5.8 and c = 4
s = a+b+c/2
s= 8.6+5.8+4/2
s= 9.2
Area of triangle=
So, area of triangle is 9.88 units^2
<span>Selection A is correct</span>
The answer is: Substitution property of equality.
The explanation is shown below:
1. To solve this problem you must apply the proccedure shown below:
2. When you clear the variable x from the first equation, and subtitute it into the second equation, you obtain:
<span>3x−2y=10
x=(10+2y)/3
4x−3y=14
</span>4[(10+2y)/]−3y=14
<span> y=-2
3. When you subsitute y=-2 into the first equation and clear the x, you have:
x=2
</span>
Answer: No
Step-by-step explanation: There 2 different things