Answer:
First term: 5
Fourth term: 5 1/2
Tenth term: 6 1/2
Step-by-step explanation:
Let's find the first, fourth and tenth terms of the arithmetic sequence described by the given rule:
A(n) = 5 + (n-1) (1/6)
First term:
A(1) = 5 + (1-1) (1/6)
A(1) = 5 + (0) (1/6)
A(1) = 5
Fourth term:
A(4) = 5 + (4-1) (1/6)
A(4) = 5 + (3) (1/6)
A(4) = 5 + 3/6 = 5 3/6 = 5 1/2 (simplifying)
Tenth term:
A(10) = 5 + (10-1) (1/6)
A(10) = 5 + (9) (1/6)
A (10) = 5 + 9/6 = 6 3/6 = 6 1/2 (simplifying)
Answer:
(1-q^2 r^2) x (1+q^2 r^2)
X= a+b+c+bx/a(x-b) but I’m not completely sure
Answer:
226.8cm^2
Step-by-step explanation:
A=pir^2
24/4 = 6 (radius of small circles)
pi6^2= 113.097335529 times 2 (because theres 2 of them)
=226.8
24/2 = 12 (radius of big circle)
pi12^2= 452.4 minus 226.8 (to get the leftover space)
=226.8
Answer:
d.
Step-by-step explanation:
add 5+9=14
divide by 2=7
