Answer:
{2, 8}
Step-by-step explanation:
We want to find x for ...
15 = 4|x -5| +3
12 = 4|x -5| . . . . subtract 3
3 = |x -5| . . . . . . divide by 4
±3 = x -5 . . . . . . show the meaning of absolute value
5 ±3 = x = {2, 8} . . . . . add 5
The values of x for which f(x) = 15 are 2 and 8.
The expression represented by 50 added to half of a number, c is 50 + c/2
<h3>What are expressions?</h3>
Expressions are mathematical statements that are represented by variables, coefficients and operators
<h3>How to translate the algebraic expression?</h3>
The expression is given as
50 added to half of a number, c
half of a number, c means divide c by 2
So, we have
50 added to half of a number, c => 50 added to c/2
Added to means +
So, we have
50 added to half of a number, c => 50 + c/2
Hence, the expression represented by the statement is 50 + c/2
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Complete question is;
It took Priya 5 minutes to fill a cooler with 8 gallons of water from a faucet that was flowing at a steady rate. Let w be the number of gallons of water in the cooler after t minutes. Which of the following equations represent the relationship between w and t? Select all that apply
A) w = 1.6t
B) w = 0.625t
C) t = 1.6w
D) t = 0.625w
Answer:
Option A: w = 1.6t
& Option D: t = 0.625w
Step-by-step explanation:
We are told It took Priya 5 minutes to fill a cooler with 8 gallons of water at a steady rate.
Thus;
Rate of filling = 8 gallons/5 minutes = 1.6 gallons/minutes
Now, we are told that w is the number of gallons of water in the cooler after t minutes.
Thus, to find w, we will multiply the rate by t minutes.
w = 1.6 gallons/minutes × t minutes
w = 1.6t gallons
Or we can write as;
w/1.6 = t gallons
0.625w = t gallons
Therefore, options A & D are correct.
Answer:
Elevation in boiling point is mathematically expressed as
ΔTb = Kb X m
where Kb = boiling point elevation constant = 2.53°c/m (for benzene)
m = molality of solution = 3.47 m (given)
∴ ΔTb = 2.53 X 3.47
= 8.779 oC
But, boiling point of benzene = 80.1 oC
∴ Boiling point of solution = 88.879 oC
Now, Depression in freezing point = ΔTf = Kf X m
where, Kf = freezing point depression constant = 5.12°c/m (for benzene)
∴ ΔTf = 5.12 X 3.47
= 17.766 oC
But freezing point of benzene = 5.5 oC
∴ Freezing point of solution = -12.266 oC
