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Gwar [14]
3 years ago
11

Type the correct answer in each box. Use numerals instead of words.

Mathematics
1 answer:
Dmitrij [34]3 years ago
7 0

Answer:

wrong impression, please check the question again

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What is 5/4 divided by 1/3
koban [17]
The answer is !5/ 4 because when dividing a fraction by a fraction you multiply the first fraction by the second fractions reciprocal. 
4 0
3 years ago
Read 2 more answers
Factor: 9x^2 + 15x.
slega [8]

Answer:

3(3x^2 + 5)

Step-by-step explanation:

step 1: find out the greatest common factor (GCF) of the number 9 and 15

ex: 9x^2 + 15x   (3 * 3x^2 + 3 * 5)

step 2: factor out the common term 3

ex: 3 * 3x^2 + 3 * 5   (3 * 3x^2 + 5)

step 3: simplify the equation

3 * 3x^2 + 5   [3(3x^2 + 5)]

6 0
3 years ago
X^2 = 1/100, what is x​
Contact [7]

X in (-oo:+oo)

X^2 = 1/100 // - 1/100

X^2-(1/100) = 0

X^2-1/100 = 0

1*X^2 = 1/100 // : 1

X^2 = 1/100

X^2 = 1/100 // ^ 1/2

abs(X) = 1/10

X = 1/10 or X = -1/10

X in { 1/10, -1/10 }

6 0
3 years ago
Read 2 more answers
WILL GIVE BRAINLIST SOON AS I CAN can someone please help me out here ​
BabaBlast [244]

Answer:

x = 6

Step-by-step explanation:

Since the 2 base angles of the triangle are congruent, both 45°, then

The figure is a right isosceles triangle, thus the 2 legs are congruent, that is

x = 6

8 0
3 years ago
Use Algorithm 7 to schedule the largest number of talks in a lecture hall from a proposed set of talks, if the starting and endi
3241004551 [841]

Answer:

If we arrange the talks from the lowest starting time to the highest ending time we get total of 11 talks.

using algorithm 7 we get answer   (1) - (3) - (6) - (9)   the largest number of talks scheduled.

Step-by-step explanation:

arranging the talks from lowest starting time to the highest ending time.

thus,

  1. 9:00 a.m. and 9:45 a.m.
  2. 9:30 a.m. and 10:00 a.m.
  3. 9:50 a.m. and 10:15 a.m.
  4. 10:00 a.m. and 10:30 a.m.
  5. 10:10 a.m. and 10:25 a.m.
  6. 10:30 a.m. and 10:55 a.m.
  7. 10:15 a.m. and 10:45 a.m.
  8. 10:30 a.m. and 11:00 a.m.
  9. 10:45 a.m. and 11:30 a.m.
  10. 10:55 a.m. and 11:25 a.m.
  11. 11:00 a.m. and 11:15 a.m.

we start from the earliest time as

9:00 a.m. and 9:45 a.m which is (1).

After the talk is finished we pick the nearest time for another talk which starts at

9:50 a.m. and 10:15 a.m which is (3).

After this talk we again pick the nearest time for another talk which becomes

10:30 a.m. and 10:55 a.m which is (6).

and lastly

10:45 a.m. and 11:30 a.m which is (9).

Note: we didn't choose other times because we cannot talk at 2 or 3 places at the same time. so we pick another when one talk is finished.

thus the answer is (1) - (3) - (6) - (9) as the largest number of talks scheduled.

4 0
3 years ago
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