Answer:
A. VG = 80
B. Broad sense heritability = 0.80
C. Narrow sense heritability = 0.30
D. Average yield = 430 Units
Explanation:
A. Given that
VA = 30
VD = 50
VI = assumed not available
Therefore
Total genetic variance (VG) = VA + VD
= 30 + 50
= 80
VG = 80
B. Given that
VP = 100
VG = 80
Broad sense heritability, H2 = VG/VP
= 80/100
= 0.80
C. Given that
VA = 30
VP = 100
Narrow sense heritability, h2 = VA/VP
=30/100
= 0.30
D. The difference in selection = 500 - 400
= 100
Recall,
Selection response is heritability multiplied by selection differential.
That is
R = h2S
Selection differential = 100
Heritability h2 = 0.30
Selection response = 0.30 × 100
= 30units
Therefore, expected average yield = 400 + 30
= 430 Units
Answer:
a. on the outer surface of the epiphyses.
Explanation:
Articular cartilage of a long bone is found on the outer surface of the epiphyses.
The estimated expected (mean) time for project completion is 50 weeks, time management includes all the activities necessary to achieve the target date of delivery of the project. It includes the following activities: identification of activities, logical sequencing of activities, estimation of duration of activities, and preparation of the project schedule. For the preparation of the schedule we will see various methods such as resource leveling, simulation, and the critical chain method.
