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vazorg [7]
3 years ago
6

You typed the word "weather" when you meant to type the word "whether." When will Writer or Word flag this as a misspelling or a

grammar problem
Computers and Technology
2 answers:
maria [59]3 years ago
4 0

Answer:

It depends on the structure of the sentence.

Explanation:

This will be shown as grammatical mistake because both the spellings are correct. If we write the word weather instead of the whether, Ms word shows the grammatical mistake. This is because, if we want to write the word whether, we should use or in our sentence. Both of these words are comes together.

Example

I will take a leave whether its raining or not.

In above sentence, both whether and or comes together. If we write weather instead of whether it just show the grammatical mistake in the sentence.

Gala2k [10]3 years ago
4 0

Answer:

depends on the rest of the sentence and how you have your settings for grammar and spell checker

Explanation:

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Given: an int variable k, an int array current Members that has been declared and initialized, an int variable memberID that has
Alekssandra [29.7K]

Answer:

The c++ program is given below. Nothing is displayed as per the question.

#include <iostream>

using namespace std;

int main() {    

   // declaration and initialization of integer variables

   int k, memberID = 12, nMembers=5;

   bool isAMember;    

   // declaration and initialization of integer array

   int currentMembers[] = {12, 34, 56, 78, 90};    

   for(k=0; k<nMembers; k++)

   {

       if(memberID == currentMembers[k])

       {

           // when member is found in the array, the loop is exited using break

           isAMember = true;

           break;

       }

       else

           isAMember = false;

   }    

   return 0;

}

Explanation:

The program begins with declaration and initialization of integer variables and followed by initialization of the array holding the id of all the members.

The Boolean variable is declared but not initialized.

int k, memberID = 12, nMembers=5;

bool isAMember;

int currentMembers[] = {12, 34, 56, 78, 90};

After this, the array holding the id of the members is searched for the given member id. This is done using  a for loop and a if else statement inside the loop.

If the member id is present in the array, the variable isAMember is initialized to true otherwise it is assigned false.

When the variable isAMember is initialized to true, the break statement is used to exit from the loop.

for(k=0; k<nMembers; k++)

   {

       if(memberID == currentMembers[k])

       {

           isAMember = true;

           break;

       }

       else

           isAMember = false;

 }

The break is used since other values of id in the array will not match the given member id and the variable, isAMember will be initialized to false even if the given member id is present in the array. Hence, it is mandatory to exit the loop once the given member id is found in the array.

This program can be tested for different values of the id of the members and different sizes of the array.

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