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maksim [4K]
3 years ago
11

How do i block somebody on here, theyre making me have a panic attack. /srs

Computers and Technology
2 answers:
Naya [18.7K]3 years ago
7 0

Give that man a branliest!!

spin [16.1K]3 years ago
5 0

Answer:

If someone is disturbing you a lo then you can report him/her.

  • Go to g-mail.
  • Type a message to US Support.
  • Add a screenshot of him/her whom you want to report.
  • Use polite words
  • At last, send it.

You will get soon response.

You might be interested in
Write a Java program in jGRASP that creates a 2D integer array of 5 rows and 20 columns, fills it with increasing integer values
Alex73 [517]

Answer:

As per the question we need to make 5 rowa and 2o columns, in this we have total element 100 so range should be 0 to 99, but we are suggested to keep range 0 to 59, so i have kept the elementns in the range, but if it was a typo in the question for range you do not need to reset the k with zero.

Explanation:

//create a new class  TestArray

public class TestArray {

//define main method

public static void main(String[] args) {

 //declare a 2D array of given size i.e. 5 rows and 20 columns

 int arr[][] = new int[5][20];

 //declare an integer variable k and initialize it with zero, this will used to initialize the array from 0 to 99

 int k = 0;

 //for loop for rows

 for (int i = 0; i < 5; i++) {

  //for loop for columns

  for (int j = 0; j < 20; j++) {

   //initialize arr with the current value of k

   arr[i][j] = k;

   //once k is 59 set it zero again as we are not going beyond 59

   if(k == 59)

    k = 0;

   //increment value of k with 1

   k++;

  }

 }

 //print the element from the array one by one

 //for loop for rows

 for (int i = 0; i < 5; i++) {

  //for loop for columns

  for (int j = 0; j < 20; j++) {

   //print the current element of array and an space with it

   System.out.print(arr[i][j]+" ");

  }

  // move the cursor to new line

  System.out.println();

 }

}

}

7 0
3 years ago
2. When a business practices offensive behavior, you have many options. The option with the loudest voice is
Andreas93 [3]
—-_-__-____- _—-_- -__-_-____-__




___-_-_ _- —|
4 0
2 years ago
An excel file called “student_gpa” is opened. What does the funnel next to “GPA” indicate
Ivan

Answer is A. The data has been filtered

The funnel in Excel lets you know that there is a filter in place on the columns. It is a filter icon. By default, any filtered column in Excel gets a little funnel icon on the top row as shown in the image attached. Once this funnel symbols is clicked, it gives you options to filter using several criteria.

6 0
3 years ago
Why is it important to record audio of silence in the area in which you are filming?
Serhud [2]

Answer:

To make sure that there is no other outside/excess noise while you are filming your actual film

Hoped this helped !

Cheers, Z

3 0
3 years ago
Read 2 more answers
I have six nuts and six bolts. Exactly one nut goes with each bolt. The nuts are all different sizes, but it’s hard to compare t
juin [17]

Answer:

Explanation:

In order to arrange the corresponding nuts and bolts in order using quicksort algorithm, we need to first create two arrays , one for nuts and another for bolts namely nutsArr[6] and boltsArr[6]. Now, using one of the bolts as pivot, we can rearrange the nuts in the nuts array such that the nuts on left side of the element chosen (i.e, the ith element indexed as nutArr[i]) are smaller than the nut at ith position and nuts to the right side of nutsArr[i] are larger than the nut at position "I". We implement this strategy recursively to sort the nuts array. The reason that we need to use bolts for sorting nuts is that nuts are not comparable among themselves and bolts are not comparable among themselves(as mentioned in the question)

The pseudocode for the given problem goes as follows:

// method to quick sort the elements in the two arrays

quickSort(nutsArr[start...end], boltsArr[start...end]): if start < end: // choose a nut from nutsArr at random randElement = nutsArr[random(start, end+1)] // partition the boltsArr using the randElement random pivot pivot = partition(boltsArr[start...end], randElement) // partition nutsArr around the bolt at the pivot position partition(nutsArr[start...end], boltsArr[pivot]) // call quickSort by passing first partition quickSort(nutsArr[start...pivot-1], boltsArr[start...pivot-1]) // call quickSort by passing second partition quickSort(nutsArr[pivot+1...end], boltsArr[pivot+1...end])

// method to partition the array passed as parameter, it also takes pivot as parameter

partition(character array, integer start, integer end, character pivot)

{

       integer i = start;

loop from j = start to j < end

       {

check if array[j] < pivot

{

swap (array[i],array[j])

               increase i by 1;

           }

 else check if array[j] = pivot

{

               swap (array[end],array[j])

               decrease i by 1;

           }

       }

swap (array[i] , array[end])

       return partition index i;

}

7 0
3 years ago
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