Perimeter of a rectangle = 2(l+w)
Length = 4-7(3x+4y)
=4-21x-28y
Width = 3x(-2y)
=-6xy
Perimeter
=2(4-21x-28y-6xy)
Answer = 8-42x-56y-12xy
Surface area of cylinder = 2πrh + 2πr^2
SA for cylinder A = 2π x 2 x 2 + 2π x (2)^2 = 8π + 8π = 16π
SA for cylinder B = 2π x 2 x 4 + 2π x (2)^2 = 16π + 8π = 24π
2x - 3y = -24
x+ 6y = 18
you solve the first one by the x:
2x = -24 + 3y
x = (-24+3y)/2
then you substitute what you found in the other equation and you solve by y
(-24+3y)/2 + 6y = 18 multiply everything by 2
-24 + 3y + 12y = 36
3y + 12y = 36 + 24
15y = 60
y = 60/15
y = 4
Good job! You found your y! :D
Now let's substitute the y in the first equation with 4:
2x - 3(4) = -24
2x - 12 = -24
2x = -24 + 12
2x = -12
x = -12/2
x= -6
Done!! ;) <span />
Answer: B) James Madison
Step-by-step explanation:
AC and AB are tangents to circle O, meaning that the angles C and B are right angles of 90 degrees. Since a quadrilateral's internal angles must sum up to 360 degrees, this means that A + B + C + O = 360
70 + 90 + 90 + O = 360
O = 110 degrees.
