I need help solving a system of linear equation, and it says to solve it by Substitution.
2 answers:
First solve for x in the second equation (x=-6y+18).then substitute -6y+18 in the first equation and solve for y.after solving for y then substitute it in one of the equation and then solve for x. 2x-3y=-25 x+6y=18 x=-6y+18 2(-6y+18)-3y=-24 -12y+36-3y=-24 -15y+36=-24 -15y=-24-36 -15y=-60 y=4 x+6(4)=18 x+24=18 x=18-24 x=-6 y=4,x=-6
2x - 3y = -24 x+ 6y = 18 you solve the first one by the x: 2x = -24 + 3y x = (-24+3y)/2 then you substitute what you found in the other equation and you solve by y (-24+3y)/2 + 6y = 18 multiply everything by 2 -24 + 3y + 12y = 36 3y + 12y = 36 + 24 15y = 60 y = 60/15 y = 4 Good job! You found your y! :D Now let's substitute the y in the first equation with 4: 2x - 3(4) = -24 2x - 12 = -24 2x = -24 + 12 2x = -12 x = -12/2 x= -6 Done!! ;) <span />
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