Find a third number so that numbers form a right triangle 13,85

Mathematics

1 answer:

crimeas [40]3 years ago

3 0

Answer:

The third number is 84

Step-by-step explanation:

Given two numbers as 13 , 85

To make the triangle to be right angle , Pythagoras theorem is applied ,

i.e H² = P² + B²

Here H = 85 ,

Let perpendicular = x and base = 13

So, P² = H² - B²

Or, x² = 85² - 13²

Or, x² = 7225 - 169

Or, x² = 7056

i.e x = $\sqrt{7056}$ = 84

Hence, the third number to make it right triangle = 84 Answer

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Answer:

Step-by-step explanation:

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Again repeating the same procedure we get

$=0-\int_{0}^{\infty }\frac{3t^{2}}{-s}e^{-st}dt\\\\=\int_{0}^{\infty }\frac{3t^{2}}{s}e^{-st}dt\\\\\int_{0}^{\infty }\frac{3t^{2}}{s}e^{-st}dt= \frac{3}{s}[t^2\int e^{-st} ]_{0}^{\infty}-\int_{0}^{\infty }[(t^2)\int e^{-st}dt]dt\\\\=\frac{3}{s}[0-\int_{0}^{\infty }\frac{2t^{1}}{-s}e^{-st}dt]\\\\=\frac{3\times 2}{s^{2}}[\int_{0}^{\infty }te^{-st}dt]\\\\$

Again repeating the same procedure we get

$\frac{3\times 2}{s^2}[\int_{0}^{\infty }te^{-st}dt]= \frac{3\times 2}{s^{2}}[t\int e^{-st} ]_{0}^{\infty}-\int_{0}^{\infty }[(t)\int e^{-st}dt]dt\\\\=\frac{3\times 2}{s^2}[0-\int_{0}^{\infty }\frac{1}{-s}e^{-st}dt]\\\\=\frac{3\times 2}{s^{3}}[\int_{0}^{\infty }e^{-st}dt]\\\\$