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2 years ago

A submarine starts 15 meters above sea level and travels 95 meters below sea level. How far did the submarine travel? *

Mathematics

1 answer:

Yuliya22 [10]2 years ago

7 0

The height attained by the submarine in the sea will be 80 meters.

<h3>What is the height?</h3>

Height is a vertical distance travelled by any object. Here the submarine is going down in the sea from 15 meters to 95 meters below the sea.

So the height attained by the submarine will be:-

H= 95-15

H= 80 meters.

Therefore the height attained by the submarine in the sea will be 80 meters.

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Now, we should to proof that $\triangle EFH \cong \triangle GHF$ . The simbol "≅" means congruence, that is, $\triangle EFH \cong \triangle GHF$ means that the triangles EFH and GHF are equals.

Let's proof:

$\overline{HF}$ is a diagonal of the parallelogram EFGH. When we have a diagonal in a parallelogram, the opposite angles are congruents (look at the picture: the blue angles are congruent and the red angles are congruents too). Therefore, $E\hat{F}H \cong F\hat{H}G$ and $E\hat{H}F \cong H\hat{F}G$ .

Both triangle has a comum side: the diagonal $\overline{HF}$ . The diagonal $\overline{HF}$ is between two angles that we know that are congruents, Therefore, by the case ASA (Angle, Side, Angle), we proof that $\triangle EFH \cong \triangle GHF$ .