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Volgvan
2 years ago
14

A submarine starts 15 meters above sea level and travels 95 meters below sea level. How far did the submarine travel? *

Mathematics
1 answer:
Yuliya22 [10]2 years ago
7 0

The height attained by the submarine in the sea will be 80 meters.

<h3>What is the height?</h3>

Height is a vertical distance travelled by any object. Here the submarine is going down in the sea from 15 meters to 95 meters below the sea.

So the height attained by the submarine will be:-

H= 95-15

H= 80 meters.

Therefore the height attained by the submarine in the sea will be 80 meters.

To know more about height follow

brainly.com/question/1739912

#SPJ1

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<h3><u>Question:</u></h3>

Serena uses chalk to draw a straight line on the sidewalk. The line is 1/2 ft long. She wants to divide the line into sections that are each 1/8 ft long. How many sections will the line be divided into?

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<h3><u>Solution:</u></h3>

Given that, Serena uses chalk to draw a straight line on the sidewalk

The line is 1/2 ft long. She wants to divide the line into sections that are each 1/8 ft long

From given,

Total\ length\ of\ line = \frac{1}{2} \text{ feet }\\\\Length\ of\ each\ section = \frac{1}{8} \text{ feet }

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The number of sections that can be made is found by dividing the total length of line by length of each section

\text{Number of sections } = \frac{\text{Total length of line}}{\text{length of each section}}

Substituting the values, we get,

\text{Number of sections } = \frac{\frac{1}{2}}{\frac{1}{8}}\\\\\text{Number of sections } = \frac{1}{2} \times \frac{8}{1}\\\\\text{Number of sections } = 4

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