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3 years ago

What are the dimensions of the poster at one-third its current size?

Mathematics

1 answer:

Slav-nsk [51]3 years ago

5 0

Answer:

you enter x 1/3 and will get the answer.

You haven't given the dimensions so an example is below.

Step-by-step explanation:

Ex 1

Poster current size 60inches

60 x 1/3 = 20 = 20inches

Ex 2

Poster current size 63 inches

60 x 1/3 = 21 = 21inches

Ex 3

Poster current size 67 inches

67 x 1/3 = 22.33 = 22.33 inches

Ex 4

Poster current size 81 x 47 inches

81 x 1/3 = 27 47 x 1/3 = 15.66

This means the poster at 1/3 size is 27in x 15.66in

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What is the least common denominator for the fractions1/6and 3/4 ?

melomori [17]

A. 12; Least common denominator is the least multiple that the denominator have together. So you multiply the denominators until you get the first number they both have in common.
6*1 = 6
6*2 =12

4*1 =4
4*2 =8
4*3 = 12

Since the first number they both have in common is 12, the least common denominator is 12

3 0

3 years ago

3 out of 4 students surveyed said they walk to school. The difference between the number of students who walk to school and who

Rina8888 [55]

Answer:

Step-by-step explanation:

3/4x-1/4x=36

1/2x=36

x=72

Please mark me as Brainliest if possible

8 0

2 years ago

$9.40 per hour times 22 hours round to the nearest cent

REY [17]

Answer:

The answer is 206.8. But you want me to round to the nearest cent so the real answer is $207.00

Step-by-step explanation:

4 0

3 years ago

What method can be used to write the equation of a line in slope-intercept form given two points? Find the slope using the formu

Lapatulllka [165]

Answer: B

Step-by-step explanation:

Step-by-step explanation: Find the slope using the formula m = StartFraction x 2 minus x 1 Over y 2 minus y 1 EndFraction, and then substitute one point and the slope into the equation y = m x + b to find the y-intercept.

7 0

3 years ago

Apply Gaussian quadrature with n = 4 to approximate integrate sin x^2dx from 1 to 5

maks197457 [2]

First, recall that Gaussian quadrature is based around integrating a function over the interval [-1,1], so transform the function argument accordingly to change the integral over [1,5] to an equivalent one over [-1,1].

$x=2t+3\iff t=\dfrac x2-\dfrac32\implies2\mathrm dt=\mathrm dx$
$x=1\implies t=\dfrac{2-6}4=-1$
$x=5\implies t=\dfrac{10-6}4=1$

So,

$\displaystyle\int_{x=1}^{x=5}\sin x^2\,\mathrm dx=\displaystyle2\int_{t=-1}^{t=1}\sin(2t+3)^2\,\mathrm dt$

Let $f(t)=2\sin(2t+3)^2$ . With $n=4$ , we're looking for coefficients $c_i$ and nodes $x_i$ , with $1\le i\le4$ , such that

$\displaystyle\int_{-1}^1f(t)\,\mathrm dt\approx c_1f(x_1)+\cdots+c_4f(x_4)$

You can either try solving for each with the help of a calculator, or look up the values of the weights and nodes (they're extensively tabulated, and I'll include a link to one such reference).

Using the quadrature, we then have

$\displaystyle\int_{-1}^1f(t)\,\mathrm dt\approx0.3749f(-0.8611)+0.6521f(-0.3400)+0.6521f(0.3400)+0.3749f-0.8611)$
$\displaystyle\int_{-1}^1f(t)\,\mathrm dt\approx0.5790$

4 0

3 years ago