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julsineya [31]
2 years ago
10

PLEASE HELP

Mathematics
1 answer:
Simora [160]2 years ago
7 0

The value of <em>b</em> so that 3 · x² + b · x - 24 has the same <em>x</em>-intercepts (only one <em>x</em>-intercept) is 12 √2.

<h3>How to determine a missing coefficient in a second order polynomial</h3>

<em>Second order</em> polynomials are represented graphically by parabolae and it may have two, one or no <em>x</em>-intercepts. The quantity of <em>x</em>-intercepts can be deducted from the discriminant of the quadratic formula, which is defined below:

For <em>a · x² + b · x + c = 0</em>, the discriminant is defined by:

<em>d = b² - 4 · a · c</em>   (1)

There are three rules to determine the number of possible intercepts:

  1. If <em>d < 0</em>, then there are no <em>x</em>-intercepts.
  2. If <em>d = 0</em>, then there is only one <em>x</em>-intercept.
  3. If <em>d > 0</em>, then there are two <em>x</em>-intercepts.

Then, we have to find a value of <em>b</em> so that (1) has the following form:

<em>b² - 4 · 3 · (-24) = 0</em>

<em>b² - 288 = 0</em>

<em>b = 12√ 2</em>

The value of <em>b</em> so that 3 · x² + b · x - 24 has the same <em>x</em>-intercepts (only one <em>x</em>-intercept) is 12 √2. \blacksquare

<h3>Remark</h3>

The answer choices do not correspond with the given statement, the phrase "same x-intercepts" may lead to confusion and possible graph cannot be found. A possible corrected statement is shown below:

<em>The graph of g(x) = 3 · x² + b · x - 24 has only one x-intercept. What is the value of </em><em>b</em><em>?</em>

To learn more on parabolae, we kindly invite to check this verified question: brainly.com/question/10572747

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Find the vertex for the parabola given by the function ƒ(x) = −3x2 − 6x.
Montano1993 [528]

Answer:

The vertex of the parabola is (-2,0)

Step-by-step explanation:

The given function is:

f(x)=-3x^{2}-6x

Now, in order to find the vertex for the parabola, that is v(h,k), comparing the above equation with the standard form of equation that is f(x)=ax^{2}+bx+c, we get

a=-3, b=-6 and c=0

We know, h=\frac{-b}{2a} and k=f(h), therefore

h=\frac{6}{-3}=2 and f(h)=f(-2)=-3(-2)^{2}-6(-2)

f(h)=-3(4)+12=-12+12=0

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Need help filling in the blanks: selling price using markup.
Xelga [282]

Answer:

Refer to the explanation.

Step-by-step explanation:

Let's take each one at a time.

1.

To solve for the complement, we simply subtract our markup rate by 100%.

100% - 30% = 70%

Now to solve for the selling price, we use the formula

SellingPrice=\dfrac{Cost}{ComplementOfMarkupRate}

SellingPrice=\dfrac{86.74}{0.70}

Selling Price = $123.91

2.

We do the same process with the first number.

100% - 40% = 60%

SellingPrice=\dfrac{Cost}{ComplementOfMarkupRate}

SellingPrice=\dfrac{220.00}{0.60}

SellingPrice = $366.67

3.

The same as the first two.

100% - 20% = 80%

SellingPrice=\dfrac{Cost}{ComplementOfMarkupRate}

SellingPrice=\dfrac{89.50}{0.80}

SellingPrice = $111.88

4.

Now to solve for the markup rate, we use the formula:

MarkupRate=\dfrac{Markup}{SelingPrice}

In this case we first need to find the markup. The markup is the difference between the selling price and the cost.

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Markup = $35.29

Now the we know our markup, we can then solve for the markup rate using the formula.

MarkupRate=\dfrac{Markup}{SelingPrice}

MarkupRate=\dfrac{35.29}{235.28}

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5.

Now for the last one, we need to find for the cost. Let's use the selling price formula to find for the cost.

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We multiple both sides of the equation by 0.65 to leave our cost alone.

30.77 x 0.65 = Cost

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Papessa [141]

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<h3>What is factored form?</h3>

The product of a constant and two linear expressions in factored form. The roots of the function are the parameters and the x-intercepts of the graph. Often Factoring is referred to as the process of converting a quadratic function to factored form.

We need to write the given expression 9x^4y-6x^3y^2 + 3x^2y^3 in the factored form, therefore, we will take the common terms out of the given expression,

1. Taking 3 as the common term, we will get,

9x^4y-6x^3y^2 + 3x^2y^3\\\\= 3 (3x^4y-2x^3y^2 + x^2y^3)

2. Taking x² as the common term

= 3 (3x^4y-2x^3y^2 + x^2y^3)\\\\= 3x^2(3x^2y-2xy^2+y^3)\\\\

3. Taking y as the common term,

= 3x^2(3x^2y-2xy^2+y^3)\\\\= 3x^2y(3x^2-2xy+y^2)\\\\

Hence, the factored form of the equation 9x⁴y - 6x³y² + 3x²y³ is 3x²y(3x²-2xy+y²).

Learn more about Factored Form:

brainly.com/question/25094938

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