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inessss [21]
3 years ago
13

Write a slope intercept equation for a line passing through the point (4,-2) that is parallel to the line 4x+5y=7. Then write a

second equation for a line passing through the point (4,-2) that is perpendicular to the line 4x+5y=7
Mathematics
1 answer:
LuckyWell [14K]3 years ago
3 0

First, the equation needs to be put into slope-intercept form, which is y = -4/5x + 7/5. Then, you need to know what parallel and perpendicular lines are. REMEBER, parallel lines have the same slope, and perpendicular lines have slopes whose product equal -1. You just need to substitute. For the parallel line, -2 = -4/5(4) + b, and b = 6/5, so y = -4/5x + 6/5. For the perpendicular line, the slope is 5/4. Now substitute. -2 = 5/4(4) + b, and b = -7, so y = 5/4x -7.

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3 years ago
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3 years ago
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IrinaVladis [17]

Hello from MrBillDoesMath!

Answer:  x = 1

Discussion :

Per the author, the equation to solve is  12 = 5x + 7

Isolate the "x" variable by subtracting 7 from both sides of the equation:

12 = 5x + 7

-7 =        -7

---------------------

12-7 = 5x + 0


or


5 = 5x

Dividing both sides by 5 gives x - 1


Regards, MrB

6 0
3 years ago
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7 0
3 years ago
Read 2 more answers
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