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3 years ago

11

Slove using linear combation 11x+4y=18 3x+4y=2

1 answer:

Sergeeva-Olga [200]3 years ago

5 0

Answer:

x=2, y= -1 (2,-1)

Step-by-step explanation:

4y=2-3x

11x+(2-3x)=18

8x+2=18

8x=16

x=2

22+4y=18

y=-1

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Your family goes to a Southern-style restaurant for dinner. There are 5 people in your

AURORKA [14]

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4 0

3 years ago

A similarity transformation maps polygon ABCD to polygon PQRS. If the length of is 6 and the length of the corresponding side, ,

grigory [225]

For this case, what we must do is find the scale factor.
We have then that the scale factor is given by:
$k = \frac{L1}{L2}$
Where,
L1: side length of polygon ABCD
L2: side length of polygon PQRS
Note: both sides belong to the same side of each polygon
Substituting the values we have:
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Rewriting we have:
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Answer:
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3 0

3 years ago

Read 2 more answers

Perform the indicated operation. Be sure the answer is reduced.

avanturin [10]

<h3>Given Equation:-</h3>

$\boxed{ \rm \frac{4x^{2}y^{3}z}{9} \times \frac{45y}{8 {x}^{5} {z}^{5} }}$

<h3>Step by step expansion:</h3>

$\dashrightarrow \sf\dfrac{4x^{2}y^{3}z}{9} \times \dfrac{45y}{8 {x}^{5} {z}^{3} }$

$\\ \\$

$\dashrightarrow \sf\dfrac{ \cancel4x^{2}y^{3}z}{9} \times \dfrac{45y}{ \cancel8 {x}^{5} {z}^{3} }$

$\\ \\$

$\dashrightarrow \sf\dfrac{x^{2}y^{3}z}{9} \times \dfrac{45y}{2{x}^{5} {z}^{3} }$

$\\ \\$

$\dashrightarrow \sf\dfrac{x^{2}y^{3}z}{ \cancel9} \times \dfrac{ \cancel{45}y}{2{x}^{5} {z}^{3} }$

$\\ \\$

$\dashrightarrow \sf\dfrac{x^{2}y^{3}z}{1} \times \dfrac{5y}{2{x}^{5} {z}^{3} }$

$\\ \\$

$\dashrightarrow \sf\dfrac{x^{0}y^{3}z}{1} \times \dfrac{5y}{2{x}^{5 - 2} {z}^{3} }$

$\\ \\$

$\dashrightarrow \sf\dfrac{y^{3}z}{1} \times \dfrac{5y}{2{x}^{3} {z}^{3} }$

$\\ \\$

$\dashrightarrow \sf\dfrac{y^{3}z {}^{0} }{1} \times \dfrac{5y}{2{x}^{3} {z}^{3 - 1} }$

$\\ \\$

$\dashrightarrow \sf\dfrac{y^{3}}{1} \times \dfrac{5y}{2{x}^{3} {z}^{2} }$

$\\ \\$

$\dashrightarrow \sf \dfrac{5y \times {y}^{3} }{2{x}^{3} {z}^{2} }$

$\\ \\$

$\dashrightarrow \sf \dfrac{5y {}^{0} \times {y}^{3 + 1} }{2{x}^{3} {z}^{2} }$

$\\ \\$

$\dashrightarrow \sf \dfrac{5 \times {y}^{4} }{2{x}^{3} {z}^{2} }$

$\\ \\$

$\dashrightarrow \bf \dfrac{5 {y}^{4} }{2{x}^{3} {z}^{2} }$

$\\ \\$

$\therefore \underline{ \textbf{ \textsf{option \red c \: is \: correct}}}$

8 0

2 years ago

Need help with question 2

yuradex [85]

1,5,8 would be the correct answer

8 0

3 years ago

Read 2 more answers

Tyna simplified the expression StartFraction 3 x cubed Over 12 x Superscript negative 2 Baseline EndFraction to StartFraction x

Yuki888 [10]

Answer:

She divided the coefficients incorrectly

Step-by-step explanation:

A. She divided the coefficients incorrectly.

B. She added the exponents instead of subtracting them.

C. She divided the coefficients instead of subtracting them.

D. She subtracted the exponents instead of dividing them.

Correct calculation:

3x³/12x^-2

= 3x³ ÷ 12x^-2

= 3x³ ÷ 1/12x²

= 3x³ × 12x²/1

= 36x^5

Tyna's calculation:

3x³/12x^-2 = x/4

3 0

3 years ago