All categories

3 years ago

I really need help with these math problems

Mathematics

2 answers:

8090 [49]3 years ago

6 0

Answer:

ok the last option is for the middle one and I think the vocabulary one goes with the second one of the options sorry I dont know anything else

cricket20 [7]3 years ago

3 0

Answer:

GCF is 8

GCD is 8

GPF I'm not sure

the product of the prime factors- idk

19. 14

20. 12

7. 3

8. 14

9. 1

10. 13

11. 17

12. 1

hope this helps!!!

can you also please mark me as brainliest?

thanks

You might be interested in

A sports team has a cooler that holds 20.25 L of fluid. After practice, each of the 11 players drinks 0.95 L of sports drink.

Nitella [24]

11 x 0.95 L = 10.45 L so then 20.25 L - 10.45 L = 9.8 L

3 0

3 years ago

Keisha is planning a barbecue for her family. there will be 9 people in attendance at the barbecue. Each person can eat 3/4 of a

disa [49]

T_Bone steak because it cost less

5 0

3 years ago

Read 2 more answers

Find the average value of the function f(t)=cos13(5t)sin(5t) f(t)=cos13⁡(5t)sin⁡(5t) on the interval [4,10].

Vilka [71]

The average value is given by

$\displaystyle\frac1{10-4}\int_4^{10}\cos^{13}5t\sin5t\,\mathrm dt$

Setting $y=\cos5t$ , you get $\mathrm dy=-5\sin5t\,\mathrm dt$ , and the integral becomes

$\displaystyle-\frac1{30}\int_{\cos20}^{\cos50}y^{13}\,\mathrm dy$
$=-\dfrac1{30}\dfrac{y^{14}}{14}\bigg|_{y=\cos20}^{y=\cos50}$
$=-\dfrac{\cos^{14}50-\cos^{14}20}{420}\approx-0.00145$

6 0

4 years ago

Is anyone good at paralleligram?!I will mark brainlest.for 13 points

Black_prince [1.1K]

Answer:

Y= 15

x = 12

Step-by-step explanation:

Okay, so the sides that are across from eachother, are always equal to eachother, in a parallelogram.

So, 5y-20 = 2y + 25

Next, you add 20 to both sides, and then subtract 2 from the right side, and subtract 2 from the left side ,and you get 3y = 45

divide 45 by 3 , and you get 15.

DO the same thing for the X's.

4 0

3 years ago

Q.6. The equation of the ellipse whose centre is at the origin and the x-axis, the major axis, which passes

azamat

<h3>Answer:</h3>

Equation of the ellipse = 3x² + 5y² = 32

<h3>Step-by-step explanation:</h3>

<h2>Given:</h2>

The centre of the ellipse is at the origin and the X axis is the major axis

It passes through the points (-3, 1) and (2, -2)

The equation of the ellipse

<h2>Solution:</h2>

The equation of an ellipse is given by,

$\sf \dfrac{x^2}{a^2} +\dfrac{y^2}{b^2} =1$

Given that the ellipse passes through the point (-3, 1)

Hence,

$\sf \dfrac{(-3)^2}{a^2} +\dfrac{1^2}{b^2} =1$

Cross multiplying we get,

9b² + a² = 1 ²× a²b²
a²b² = 9b² + a²

Multiply by 4 on both sides,

4a²b² = 36b² + 4a²------(1)

Also by given the ellipse passes through the point (2, -2)

Substituting this,

$\sf \dfrac{2^2}{a^2} +\dfrac{(-2)^2}{b^2} =1$

Cross multiply,

4b² + 4a² = 1 × a²b²
a²b² = 4b² + 4a²-------(2)

Subtracting equations 2 and 1,

3a²b² = 32b²
3a² = 32
a² = 32/3----(3)

Substituting in 2,

32/3 × b² = 4b² + 4 × 32/3
32/3 b² = 4b² + 128/3
32/3 b² = (12b² + 128)/3
32b² = 12b² + 128
20b² = 128
b² = 128/20 = 32/5

Substituting the values in the equation for ellipse,

$\sf \dfrac{x^2}{32/3} +\dfrac{y^2}{32/5} =1$

$\sf \dfrac{3x^2}{32} +\dfrac{5y^2}{32} =1$

Multiplying whole equation by 32 we get,

3x² + 5y² = 32

<h3>Hence equation of the ellipse is 3x² + 5y² = 32</h3>

8 0

3 years ago