Find the measure of <2.

Mathematics

1 answer:

n200080 [17]2 years ago

6 0

Answer:

$\displaystyle 90° = m∠2$

Step-by-step explanation:

In every rhombus, when you have two diagonal segment bisectors, you will always have a circumcentre showing all midpoints of both segment bisectors, plus, it measures 90° all around, so with that being said, you have your answer.

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BartSMP [9]

Answer:
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Step-by-step explanation:
Given:
OB = 900 m
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BH/BO =tan 49
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A physics exam consists of 9 multiple-choice questions and 6 open-ended problems in which all work must be shown. If an examinee

katrin [286]

Answer: A) 1260

Step-by-step explanation:

We know that the number of combinations of n things taking r at a time is given by :-

$^nC_r=\dfrac{n!}{(n-r)!r!}$

Given : Total multiple-choice questions = 9

Total open-ended problems=6

If an examine must answer 6 of the multiple-choice questions and 4 of the open-ended problems ,

No. of ways to answer 6 multiple-choice questions

= $^9C_6=\dfrac{9!}{6!(9-6)!}=\dfrac{9\times8\times7\times6!}{6!3!}=84$

No. of ways to answer 4 open-ended problems

= $^6C_4=\dfrac{6!}{4!(6-4)!}=\dfrac{6\times5\times4!}{4!2!}=15$

Then by using the Fundamental principal of counting the number of ways can the questions and problems be chosen = No. of ways to answer 6 multiple-choice questions x No. of ways to answer 4 open-ended problems

= $84\times15=1260$