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denpristay [2]
3 years ago
15

What are the explicit equation and domain for a geometric sequence with a first term of 4 and a second term of −12?

Mathematics
1 answer:
Lerok [7]3 years ago
4 0
a_1=4;\ a_2=-12\\\\r=\dfrac{a_2}{a_1}\to r=\dfrac{-12}{4}=-3

The formula of a geometric sequence:

a_n=a_1\cdot r^{n-1}

substitute

a_n=4\cdot(-3)^{n-1}

The\ domain:\ \text{all integers where}\ n\geq1

Answer: \boxed{a_n=4(-3)^{n-1};\ \text{all integers where}\ n\geq1}
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Write a simplified expression to find the perimeter of a square with a side length of 3y units.
Murrr4er [49]

Answer:

Perimeter= 12y units

3y(4) = 12y

Step-by-step explanation:

3y + 3y + 3y + 3y= 12y

4 0
2 years ago
Which point on the number line is at 58/100
liberstina [14]

Answer:

R

Step-by-step explanation:

if you look at it 0 is the first one then count up by tens Q would 48 because it’s before 50 so 50 is right next to Q so then R is before 60 and after 50 so R is 58/100

8 0
2 years ago
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A person bought some cosmetics from wholesale market at the rate of Rs 360 per dozen he sells it at Rs 80 a pair find the gain p
bagirrra123 [75]

Given,

CP of cosmetics = Rs 360 per dozen

SP of a pair of cosmetics = Rs 80

To find,

The gain percent

Solution,

1 dozen = 12 items

CP of 1 cosmetic = 360/12 = Rs 30

SP of 1 cosmetic = 80/2 = Rs 40

Profit = SP-CP

= Rs 40 - Rs 30

= Rs 10

Profit percentage is given by :

\%=\dfrac{profit}{CP}\times 100\\\\=\dfrac{10}{30}\times 100\\\\=33.34\%

So, the profit percentage is 33.34%.

5 0
2 years ago
Help please!!!!!!!!!!!!!!!!!
krok68 [10]
C. 0.25 because you divide 0.06 by 0.24
5 0
3 years ago
A spherical balloon is being inflated at a rate of 3 cubic inches per second. Determine the change in the rate of the radius.How
Novay_Z [31]

Answer:

The rate rate of change of radius is \frac{1}{48\pi} inches per second when the diameter is 12 inches.

The radius is changing more rapidly when the diameter is 12 inches.

Step-by-step explanation:

Consider the provided information.

A spherical balloon is being inflated at a rate of 3 cubic inches per second.

The volume of sphere is V=\frac{4}{3}\pi r^3

Differentiate the above formula with respect to time.

\frac{dV}{dt}=4\pi r^2\frac{dr}{dt}

Substitute the respective values in the above formula,

3=4\pi 6^2\frac{dr}{dt}

\frac{1}{48\pi}=\frac{dr}{dt}

The rate rate of change of radius is \frac{1}{48\pi} inches per second when the diameter is 12 inches.

When d=16

3=4\pi 8^2\frac{dr}{dt}

\frac{3}{256\pi}=\frac{dr}{dt}

Thus, the radius is changing more rapidly when the diameter is 12 inches.

5 0
3 years ago
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