Question

A man ate 100 bananas in five days, each day eating 6 more than the previous day. How many bananas did he eat on the first day?​

Answer 1

The number of bananas consumed by the man on first day is 8.

Solution:

Given that  

Number of bananas consumed by man = 100

Number of day in which bananas we consumed = 5

Also given that each day eating 6 more than the previous day

Need to calculate the number of bananas consumed on first day

Let us assume number of bananas consumed of first day = x

As it is given that each day, he eats 6 more than previous day,

So number of bananas consumed on second day = number of bananas consumed of first day + 6 = x + 6

Similarly number of bananas consumed on third day = $(x +6) + 6 = x + 12$

Number of bananas consumed on fourth day = $(x + 12) + 6 = x + 18$

Number of bananas consumed on Fifth day = $(x + 18) + 6 = x + 24$

So total banana consumed in 5 days = $x + (x + 6) + (x + 12) + (x + 18) + (x + 24)$

$\Rightarrow$ Total banana consumed in 5 days = $5x + 60$

But it’s given that total banana consumed in 5 days = 100

$\Rightarrow 5 x+60=100$

On solving above expression for x, we get

$\begin{array}{l}{5 x=100-60} \\\\ {\Rightarrow x=\frac{40}{5}=8}\end{array}$

Hence number of bananas consumed on first day is equal to 8.