$2^4785733858979-|&duts7stpzo64suprxxruxpu5dp7d058d805d0y7f
30 x 0.05 = $1.5 is the answer
Answer:
![67.5\text{ [square units]}](https://tex.z-dn.net/?f=67.5%5Ctext%7B%20%5Bsquare%20units%5D%7D)
Step-by-step explanation:
The composite figure consists of one rectangle and two triangles. We can add up the area of these individual shapes to find the total area of the irregular figure.
<u>Formulas</u>:
- Area of rectangle with base
and height
:
- Area of triangle with base
and height
:
By definition, the base and height must intersect at a 90 degree angle.
The rectangle has a base of 10 and a height of 5. Therefore, its area is
.
The smaller triangle to the left of the rectangle has a base of 2 and a height of 5. Therefore, its area is
.
Finally, the larger triangle on top of the rectangle has a base of 5 and a height of 5. Therefore, its area is
.
Thus, the area of the total irregular figure is:
![50+5+12.5=\boxed{67.5\text{ [square units]}}](https://tex.z-dn.net/?f=50%2B5%2B12.5%3D%5Cboxed%7B67.5%5Ctext%7B%20%5Bsquare%20units%5D%7D%7D)
5 I think 6 I think 7 I think I just want points
The <em>correct answer</em> is:
Place the point of the compass on the vertex of our original angle. Open the compass to a random width and draw an arc through both legs of the angle. Mark the points of intersection with this arc and the sides of the angle.
Explanation:
In order to copy the angle, we need to have some reference for how wide the angle is.
So far all we have is a ray. To get the reference for the width that we need, we will construct an arc in the original angle such that it intersects each side of the angle.
We will then set the compass width to these points of intersection. This will be how we set the width of the new angle.