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BabaBlast [244]
3 years ago
13

If you can just help me with one question it would help very very much:)

Mathematics
2 answers:
cricket20 [7]3 years ago
8 0
What questions do you need help on 1,2,or3
Elanso [62]3 years ago
8 0
For (1), in geometry, when angles are vertically opposite, they are said to be equal. If one angle is 2x and the vertically opposite angle is x + 30, then we can equate them.

For (2), we will need to consider where each angle is located in relation to each other.

Vertically opposite angles are equal.

Two angles that make up a right angle are complementary. (two angles that add up to 90)

Angles in the same segment of a straight line with another line cutting the straight line are supplementary (such as angles COD and AOD) These two angles add up to 180

For (3), see above
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What is the value of a in the equation 5a – 10b = 45, when b = 3?
lara31 [8.8K]
Here you go. Do you think that you could help me with my question

5a – 10b = 45 
5a – 10(3) = 45 
5a – 30 = 45 
+30 +30 
5a = 75/5 
<span>a = 15</span>
8 0
3 years ago
Read 2 more answers
Please help with 17 and/or 18
Marizza181 [45]

Answer:

Slope Intercept Form: y=3x+10

Slope: 3

y: 10

Step-by-step explanation:

y-3x=10    Add 3x to both sides. The y has to be isolated.

So it is y=10+3x     So we have to reorder it so y=3x+10

8 0
3 years ago
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Use an online to to estimate the cost for one year at a 4 year university and one year at a 2 year college in Texas.
mart [117]
The answer is 50’ because the majority of the population is very high in Europe
6 0
3 years ago
Let P be a predicate. Determine whether or not each of the following implications is true and give a brief English explanation f
den301095 [7]

Answer:

See answer below

Step-by-step explanation:

1), Probably, your implication is ∀x∃yP(x,y)⇒∃x∀yP(x,y).

This implication is false. Consider the predicate P(x,y):="x<y" for real numbers x,y. Then, ∀x∃yP(x,y) is true: for all real x, there exists some y greater than x (take y=x+1 for example). However, ∃x∀yP(x,y) is false, as it would imply that there exists some real number x such that x is smaller than all real numbers, which is not true (real numbers do not have a minimum or a lower bound).

A short explanation would be, even if for all elements you can find one that makes a predicate true, you can not find one element that makes the predicate true for all elements.

2) Again, I assume that the predicate is ∃x∀yP(x,y)⇒∀x∃yP(x,y)

This implication is false. Consider the predicate P(x,y):="x is integer and xy=0 " for real numbers x,y. Then ∃x∀yP(x,y) is true, we need to take x=0. However, ∀x∃yP(x,y) is false, if you take x=1/2, 1/2 will never be an integer, no matter the value of y.

A short explanation would be, even if you can find one element that makes a predicate true for all elements, you can not always take an arbitrary element and find some element that makes the predicate true.

6 0
3 years ago
Plz helppppppppppppppppppppppppppp
Zolol [24]
I think the answer is b
3 0
3 years ago
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