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BabaBlast [244]
3 years ago
13

If you can just help me with one question it would help very very much:)

Mathematics
2 answers:
cricket20 [7]3 years ago
8 0
What questions do you need help on 1,2,or3
Elanso [62]3 years ago
8 0
For (1), in geometry, when angles are vertically opposite, they are said to be equal. If one angle is 2x and the vertically opposite angle is x + 30, then we can equate them.

For (2), we will need to consider where each angle is located in relation to each other.

Vertically opposite angles are equal.

Two angles that make up a right angle are complementary. (two angles that add up to 90)

Angles in the same segment of a straight line with another line cutting the straight line are supplementary (such as angles COD and AOD) These two angles add up to 180

For (3), see above
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What is the solution to the system of equations <br><br> 3x+2y=39<br> 5x-y=13
Marta_Voda [28]

3x + 2y = 39

5x - y = 13

Multiplying the last by two:

10x - 2y = 26

Adding to the first

13x = 65

x = 5

y = 5x-13 =25-13=12


Check:

3(5)+2(12)=39 good

5(5)-12=13 good


Answer: x=5, y=12


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Answer:

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Step-by-step explanation:

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What do skew lines look like
zhuklara [117]

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3 years ago
Evaulate the function at the indicated values h(t)=t+(3/t)i find h(x-1)
alex41 [277]

<span>h<span>(t)</span>=<span>t<span>34</span></span>−3<span>t<span>14</span></span></span>

Note that the domain of h is <span>[0,∞]</span>.

By differentiating,

<span>h'<span>(t)</span>=<span>34</span><span>t<span>−<span>14</span></span></span>−<span>34</span><span>t<span>−<span>34</span></span></span></span>

by factoring out <span>34</span>,

<span>=<span>34</span><span>(<span>1<span>t<span>14</span></span></span>−<span>1<span>t<span>34</span></span></span>)</span></span>

by finding the common denominator,

<span>=<span>34</span><span><span><span>t<span>12</span></span>−1</span><span>t<span>34</span></span></span>=0</span>

<span>⇒<span>t<span>12</span></span>=1⇒t=1</span>

Since <span>h'<span>(0)</span></span> is undefined, <span>t=0</span> is also a critical number.

Hence, the critical numbers are <span>t=0,1</span>.

I hope that this was helpful.

6 0
3 years ago
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