<h2>
Rate at which area is increasing is 1.08 m²/s.</h2>
Step-by-step explanation:
Area of triangle is with side a and b and angle C between them is given by
A = 0.5 ab SinC
Here we need to find how area changes with a and b fixed and C is changing,

We have
a = 8 m
b = 9 m

Substituting

Rate at which area is increasing is 1.08 m²/s.
Hello there.
<span>A density curve for all the possible ages between 0 years and 100 years is in the shape of a triangle. What is the height of the triangle?
Answer: D</span>
Answer: 
Step-by-step explanation:
Given


is given by replacing the
by
from the 

Now,
is

Answer: 272
Step-by-step explanation:
Let a1=11
a2=20
a3=29
Formula for sequence=
an=a1+(n-1)d
an = nth term
a1= first term
n= nth position
d= common difference
We are looking for the 30th term,so our n=30
d= a2-a1
d= 20-11
d= 9
Using the formula
an= a1+(n-1)d
a30= 11+(30-1)9
a30= 11+(29)9
a30= 11+(29×9)
a30= 11+261
a30= 272
Therefore, the 30th term is 272