Answer:
LHS.= Sin 2x /( 1 + cos2x )
We have , sin 2x = 2 sinx•cosx
And. cos2x = 2cos^2 x - 1
i.e . 1+ cosx 2x = 2cos^2x
Putting the above results in the LHSwe get,
Sin2x/ ( 1+ cos2x ) =2 sinx•cosx/2cos^2x
=sinx / cosx
= Tanx
.•. sin2x/(1 + cos2x)= tanx
Step-by-step explanation:
Ayou do it the exact same as whole number fractions but you might have to be more mindfull of the decimals
Step-by-step explanation:
Answer:
B. ( –3, –4)
C. ( 4, 17 )
Step-by-step explanation:
Function: y = 3x + 5
Using method of elimination
A. (2, –1)
x = 2, y = -1
-1 = 3 (2) + 5
-1 ≠ 11
This option is incorrect!
B. ( –3, –4)
x = -3, y = -4
-4 = 3 (-3) + 5
-4 = - 9 + 5
-4 = -4
This option is correct!
C. ( 4, 17 )
x = 4, y = 17
17 = 3 (4) + 5
17 = 12 + 5
17 = 17
This option is correct!
D. ( 3, 8 )
x = 3, y = 8
8 = 3 (3) + 5
8 = 9 + 5
8 = 14
This option is incorrect!
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