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timurjin [86]
3 years ago
5

the back of a moving truck is 4 feet above the ground. A ramp extending from the back of the truck meets the ground 10 feet from

the truck. What is the slope of the ramp?
Mathematics
1 answer:
IrinaVladis [17]3 years ago
6 0
The answer would be slope= rise/run=4/10=2/5.

Hope this helps!
Can u plz mark me as brainliest? I really need it!
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John has less than 15 video games what is the inequality?
lidiya [134]

Answer: well, we don't have another number so i'll use variables

VG < 15

An easy way to remember what is the lesser value is to think of an alligator; the alligator wants to eat the bigger prey so in your case the bigger prey would be 15.

6 0
3 years ago
If the perimeter of a square is 32 inches, what is the area
makvit [3.9K]

Answer:

64

Step-by-step explanation:

A square has 4 sides. 32 divided by 4 is 8. 8 squared is 64.

3 0
3 years ago
Which graph represents the function of f(x)= (4x^2-4x-8)/(2x+2)
g100num [7]

Answer:

<h2>graph <em><u>representing</u></em><em><u> </u></em><em><u>:</u></em><em><u>on</u></em><em><u> </u></em><em><u>then</u></em><em><u>.</u></em><em><u>line</u></em><em><u> </u></em><em><u>also</u></em><em><u> </u></em></h2>
6 0
3 years ago
Read 2 more answers
A container built for transatlantic shipping is constructed in the shape of a right rectangular prism. Its dimensions are 7.5 ft
Yuri [45]

Considering the definition of right rectangular prism and its volume,  the total weight of the contents is 38.81 pounds.

<h3>Right rectangular prism</h3>

A right rectangular prism (or cuboid) is a polyhedron whose surface is formed by two equal and parallel rectangles called bases and by four lateral faces that are also parallel rectangles and equal two to two.

<h3>Volume of right rectangular prism</h3>

To calculate the volume of the rectangular prism, it is necessary to find the product of its dimensions, or of the three edges that converge at a certain vertex.

That is, to calculate the volume of a rectangular prism, multiply its 3 dimensions: length×width×height.

<h3>Volume of the container </h3>

In this case, you know that:

  • the dimensions of the container built are 7.5 ft by 11.5 ft by 3 ft.
  • the container is entirely full and, on average, its contents weigh 0.15 pounds per cubic foot.

So, the volume of the container is calculated as:

7.5 ft× 11.5 ft× 3 ft= <u><em>258.75 ft³</em></u>

Then, the total weight of the contents is calculated as:

258.75 ft³×  0.15 pounds per cubic foot= <u><em>38.8125 pounds≅ 38.81 pounds</em></u>

Finally, the total weight of the contents is 38.81 pounds.

Learn more with this similar problems:

<u>brainly.com/question/13962136</u>

<u>brainly.com/question/7171617</u>

8 0
2 years ago
The Sky Ranch is a supplier of aircraft parts. Included in stock are 6 altimeters that are correctly calibrated and two that are
almond37 [142]

Answer:

For x = 0, P(x = 0) = 0.35

For x = 1, P(x = 1) = 0.54

For x = 2, P(x = 2) = 0.11

For x = 3, P(x = 3) = 0

Step-by-step explanation:

We are given that the Sky Ranch is a supplier of aircraft parts. Included in stock are 6 altimeters that are correctly calibrated and two that are not. Three altimeters are randomly selected, one at a time, without replacement.

Let X = <u><em>the number that are not correctly calibrated.</em></u>

Number of altimeters that are correctly calibrated = 6

Number of altimeters that are not correctly calibrated = 2

Total number of altimeters = 6 + 2 = 8

(a) For x = 0: means there are 0 altimeters that are not correctly calibrated.

This means that all three selected altimeters are correctly calibrated.

Total number of ways of selecting 3 altimeters from a total of 8 = ^{8}C_3

The number of ways of selecting 3 altimeters from a total of 6 altimeters that are correctly calibrated = ^{6}C_3

So, the required probability = \frac{^{6}C_3}{^{8}C_3}  

                                              = \frac{20}{56}  = <u>0.35</u>

(b) For x = 1: means there is 1 altimeter that is not correctly calibrated.

This means that from three selected altimeters; 1 is not correctly calibrated and 2 are correctly calibrated.

Total number of ways of selecting 3 altimeters from a total of 8 = ^{8}C_3

The number of ways of selecting 2 correctly calibrated altimeters from a total of 6 altimeters that are correctly calibrated = ^{6}C_2

The number of ways of selecting 1 not correctly calibrated altimeters from a total of 2 altimeters that are not correctly calibrated = ^{2}C_1

So, the required probability = \frac{^{6}C_2 \times ^{2}C_1 }{^{8}C_3}  

                                                = \frac{30}{56}  = <u>0.54</u>

(c) For x = 2: means there is 2 altimeter that is not correctly calibrated.

This means that from three selected altimeters; 2 are not correctly calibrated and 1 is correctly calibrated.

Total number of ways of selecting 3 altimeters from a total of 8 = ^{8}C_3

The number of ways of selecting 1 correctly calibrated altimeters from a total of 6 altimeters that are correctly calibrated = ^{6}C_1

The number of ways of selecting 2 not correctly calibrated altimeters from a total of 2 altimeters that are not correctly calibrated = ^{2}C_2

So, the required probability = \frac{^{6}C_1 \times ^{2}C_2 }{^{8}C_3}  

                                                = \frac{6}{56}  = <u>0.11</u>

(d) For x = 3: means there is 3 altimeter that is not correctly calibrated.

This case is not possible, so this probability is 0.

6 0
3 years ago
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