It is a
9/4=2.25*2=4.5
Hope it helps :)
Neighborhood A :
first, put the numbers in order...
2,[2,2],4,(4),5,[5,5],5
5 number summary :
minimum = 2
Q1 = 2
Q2 (median) = 4
Q3 = 5
maximum = 5
IQR = Q3 - Q1......5 - 2 = 3...so the IQR = 3
Neighborhood B :
1,[1,2],2,(3),4,[5,5],12
5 number summary :
minimum = 1
Q1 = (1 + 2) / 2 = 3/2 or 1.5
Q2 (median) = 3
Q3 = 5
maximum = 12
IQR = Q3 - Q1....5 - 1.5 = 3.5
are the box plots symmetrical ?
Neighborhood A : the median is 4.....the minimum is 2....so thats 2 spaces from the median...the maximum is 5....so thats 1 space from the median...and being that they are not the same distance from the median, ur box plot is skewed to the left...so this is not symmetrical
Neighborhood B : the median is 3....the minimum is 1....so thats 2 spaces from the median...the maximum is 12....so thats 10 spaces from the median....these are not symmetrical especially since u have an outlier of 12....this is skewed to the right
15x3$=45$
28x4$=112$
But you only had 79$
So the answer is zero
Answer: 29000 people went in 1981.
Step-by-step explanation:
Let x= Attendance in 1981.
Given: The average attendance of Everton football club fell by 7% in 1982.
Difference in attendance from 1981 to 1982 = 0.07x
If 2030 fewer people went to matches in 1982,
Hence, 29000 people went in 1981.
