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3 years ago

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using the following inequality 9 > 2. multiply each side by ( - 3 ) write a true inequality statement. 12 > -1, -27 > -

6, -27 < -6

1 answer:

HACTEHA [7]3 years ago

5 0

Answer:

-89

Step-by-step explanation:

using the following inequality 9 > 2. multiply each side by ( - 3 ) write a true inequality statement. 12 > -1, -27 > - 6,

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Jeri is a hairdresser. The table below shows the relationship between the number of clients she has per month, x, and her monthl

LenaWriter [7]

The given data is

x f(x)
---- --------
12 0
20 800
30 1800

where
x = number of clients per month
f(x) = monthly revenue

A graph of the data is shown below.
Let the equation of the line be
y = mx + c

The x-intercept is 12, therefore
12m + c = 0 (1)

The line passes through (30, 1800) and (12,0). Therefore the slope is
m = 1800/(30-12) = 100 (2)

From (1), obtain
c = -12m = -12*100 = -1200

Therefore
y = 100x - 1200

Answer: D. f(x) = 100x - 1200

3 0

3 years ago

Graph the system of inequalities. Show at least two points for each inequality. (Lesson 1.08)

rjkz [21]

The inequalities and the points are

y + 2 ≤ 5x: (5, -2) and (10, 1)
y + x > -4: (5, -2) and (10, 1)
y ≤ 1/3x: (5, -2) and (10, 1))

<h3>How to graph the system of inequalities?</h3>

The system of inequalities is given as:

y + 2 ≤ 5x

y + x > -4

y ≤ 1/3x

Next, we plot each inequality in the system of inequalities using a graphing calculator

See attachment for the graph of the system of inequalities y + 2 ≤ 5x, y + x > -4 and y ≤ 1/3x

From the attached graph, we have the following points:

y + 2 ≤ 5x: (5, -2) and (10, 1)

y + x > -4: (5, -2) and (10, 1)

y ≤ 1/3x: (5, -2) and (10, 1)

Read more about inequalities at:

brainly.com/question/24372553

#SPJ1

5 0

2 years ago

On a coordinate plane, parallelogram P Q R S is shown. Point P is at (negative 2, 5), point Q is at (2, 1), point R is at (1, ne

Anika [276]

Answer:

The perimeter of parallelogram PQRS = $2\sqrt{10}+8\sqrt{2}$ ⇒

2nd answer

Step-by-step explanation:

* <em>Lets revise some properties of the parallelogram</em>

- Each two opposite sides are parallel

- Each two opposite sides are equal

- Its <em>perimeter</em> is the <em>twice the sum of two adjacent sides</em>

* <em>Lets solve the problem</em>

∵ PQRS is a parallelogram

∵ The length of side SR is $4\sqrt{2}$

∵ The length of side QR is $\sqrt{10}$

∵ <em>SR and RQ are two adjacent sides</em>

∵ The perimeter of parallelogram PQRS = 2(RQ + SR)

∴ The perimeter of parallelogram PQRS = $2(\sqrt{10}+4\sqrt{2})$

∵ $2*\sqrt{10}$ = $2\sqrt{10}$

∵ $2*4\sqrt{2}$ = $8\sqrt{2}$

∴ The perimeter of parallelogram PQRS = $2\sqrt{10}+8\sqrt{2}$

3 0

3 years ago

Read 2 more answers

Given b(x)=|x+4| what is b(-10)

m_a_m_a [10]

$b(x)=|x+4|\\
b(-10)=|-10+4|=|-6|=6.$

8 0

4 years ago

Read 2 more answers

An experiment is conducted to determine whether intensive tutoring (covering a great deal of material in a fixed amount of time)

Rus_ich [418]

Answer:

The test statistic is t = 2.33.

Step-by-step explanation:

Before testing the hypothesis, we need to understand the central limit theorem and subtraction of normal variables.

Central Limit Theorem

The Central Limit Theorem estabilishes that, for a normally distributed random variable X, with mean $\mu$ and standard deviation $\sigma$ , the sampling distribution of the sample means with size n can be approximated to a normal distribution with mean $\mu$ and standard deviation $s = \frac{\sigma}{\sqrt{n}}$ .

For a skewed variable, the Central Limit Theorem can also be applied, as long as n is at least 30.

For a proportion p in a sample of size n, the sampling distribution of the sample proportion will be approximately normal with mean $\mu = p$ and standard deviation $s = \sqrt{\frac{p(1-p)}{n}}$

Subtraction between normal variables:

When two normal variables are subtracted, the mean is the difference of the means, while the standard deviation is the square root of the sum of the variances.

Group1 (the intensive group) consisted of 15 students and resulted in an average grade of 49.55 with a standard deviation of 10

This means that:

$\mu_1 = 49.55, s_1 = \frac{10}{\sqrt{15}} = 2.582$

Group 2 (the paced group) consisted of 17 students and resulted in an average grade of 42.29 with a standard deviation of 6.52.

This means that $\mu_2 = 42.49, s_2 = \frac{6.52}{\sqrt{17}} = 1.581$

Test if intensive tutoring is more effective than paced tutoring:

At the null hypothesis, we test that it is the same, that is, the means are the same and the subtraction is 0. So

$H_0: \mu_1 - \mu_2 = 0$

At the alternate hypothesis, we test that it is more effective, that is, the subtraction of the means is larger than 0. So

$H_a: \mu_1 - \mu_2 > 0$

The test statistic is:

$t = \frac{X - \mu}{s}$

In which X is the sample mean, $\mu$ is the value tested at the null hypothesis and s is the standard error.

0 is tested at the null hypothesis:

This means that $\mu = 0$

From the two samples:

$X = \mu_1 - \mu_2 = 49.55 - 42.49 = 7.06$

$s = \sqrt{s_1^2+s_2^2} = \sqrt{2.582^2+1.581^2} = 3.03$

Test statistic:

$t = \frac{X - \mu}{s}$

$t = \frac{7.06 - 0}{3.03}$

$t = 2.33$

The test statistic is t = 2.33.

6 0

3 years ago