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2 years ago

9

using the following inequality 9 > 2. multiply each side by ( - 3 ) write a true inequality statement. 12 > -1, -27 > -

6, -27 < -6

1 answer:

HACTEHA [7]2 years ago

5 0

Answer:

-89

Step-by-step explanation:

using the following inequality 9 > 2. multiply each side by ( - 3 ) write a true inequality statement. 12 > -1, -27 > - 6,

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I really need help with this i beg you !!

sweet-ann [11.9K]

Answer:

The perimeter and area of the square are 56 units and 196 square units, respectively.

Step-by-step explanation:

The inner right triangle represents a 45-45-90 right triangle, which has the feature of a hypotenuse whose length is $\sqrt{2}$ time the length of any of its legs. If the hypotenuse has a measure of $7\sqrt{2}$ , then the legs of the triangle have a measure of $7$ .

Now, we are aware that the side length of the square is twice the length of the leg of the right triangle. Then, side length of the square is 14 units long.

Lastly, we know from Geometry that the perimeter and area of the square are represented by the following expressions:

Perimeter

$p = 4\cdot l$ (1)

Area

$A = l^{2}$ (2)

Where $l$ is the side length of the square.

If we know that $l = 14$ , then the perimeter and area of the square are, respectively:

$p = 4\cdot (14)$

$p = 56$

$A = 14^{2}$

$A = 196$

The perimeter and area of the square are 56 units and 196 square units, respectively.

7 0

2 years ago

A solar collector is 2,0 m long by 1,5 m wide. It is held in place

icang [17]

Answer:

The width of the frame is 0.0746 meters

Step-by-step explanation:

We are told that after the frame has been attached to the solar collector, the area that is left exposed is $2.5m^2$ . As we see in the figure, the dimensions of this area are

$(w-2x)$ and $(l-2x)$

where $x$ is the width of the frame.

The product of these dimensions must equal the exposed area:

$(w-2x)(l-2x)=2.5m^2$

Now since $w=1.5m$ and $l=2m$ we have:

$(1.5-2x)(2-2x)=2.5$

we expand this and solve for x using the quadratic formula:

$4x^2-7x+3=2.5$

$4x^2-7x+0.5=0$

we get two solutions:

$x=1.6753$

$x=0.0746$

We take the second solution i.e $x=0.0746$ , because first one gives a width larger than the dimensions of the solar collector which cannot be possible.

Thus the width of the frame is 0.0746 meters.

7 0

3 years ago

Evaluate b^2 c^-1 for b = -4 and c = 2.

Burka [1]

Answer:

8

Step-by-step explanation:

b^2 c^-1

Let b=-4 and c =2

(-4)^2 * (2)^-1

The negative exponent means it is in the denominator

(-4)^2 / (2)^1

16/2

8

4 0

3 years ago

the area of a triangle is 36 sq. inches. if the base of the triangle is 6 inches, what is its height? a. 15 inches b. 6 inches c

inessss [21]

A=1/2bh
b=6
a=36
36=1/2(6)(h)
36=3h
divide both sides by 3
12=h

height=12 inches

answer is D

8 0

3 years ago

Read 2 more answers

Information reference tables the lifespan of a 60-watt lightbulb produced by a company is normally distributed with a mean of 14

irinina [24]

First, we need to standardize the value 1440 and 1465 to be able to work out the z-score

$z= \frac{1440-1450}{8.5}$
$z=-1.77$

$z= \frac{1465-1450}{8.5}$
$z=1.77$

The z-scores are shown in the diagram below

To work out the probability of $-1.77\ \textless \ z\ \textless \ 177$ we can first read on the table, the probability when $P(z\ \textless \ 1.77)=0.9616$ , then we subtract this value from 1, as we are interested in the area to the right of 1.77.

$1-0.9616=0.0384$

Then the area between $z=-1.77$ and $z=1.77$ is $1-2(0.0384)=0.9232$ which is also the probability of lifespan between 1440 and 1465

4 0

3 years ago