For this case we will complete the table part by part.
We have then:
First row:
Snake = Rabbit = 4
Rabbit = Not Snake = 18
Total = 4 + 18 = 22
Second row:
Not rabbit = Snake = 11
Not rabbit = Not Snake = 26
Total = 11 + 26 = 37
Third row:
Total = 4 + 11 = 15
Total = 18 + 26 = 44
Total = 59
Answer:
The length of the interval during which no messages arrive is 90 seconds long.
Step-by-step explanation:
Let <em>X</em> = number of messages arriving on a computer server in an hour.
The mean rate of the arrival of messages is, <em>λ</em> = 11/ hour.
The random variable <em>X</em> follows a Poisson distribution with parameter <em>λ</em> = 11.
The probability mass function of <em>X</em> is:

It is provided that in <em>t</em> hours the probability of receiving 0 messages is,
P (X = 0) = 0.76
Compute the value of <em>t</em> as follows:

Thus, the length of the interval during which no messages arrive is 90 seconds long.
Its B don't thx me
I hope I help
Answer: Team one = 1/5
Team 2 = 4/21
Team A is the fastest
Step-by-step explanation: Answer: Team one = 1/5
Team 2 = 4/21
Team A is the fastest
Step-by-step explanation: TEAM A
Tammy working alone in 1hr can clean 1/2
Melissa working alone in 1 hr can clean 1/3
working together in 1hr ,let x represent the area they will clean we have
+
= 1/x
⇒ 3 + 2 = 1/x
5 = 1/x
x = 1/5
TEAM B
Santay working alone can clean 1/4
Leticia working alone in 1 hr can clean 4/5
working together in 1 hr ,let y represent the amount they clean, we have
+
= 1/y
4 + 5/4 = 1/y
21/4 = 1/y
y = 4 /21
comparing x and y , 1/5 is greater than 4/21 , therefore Team A is faster