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Minchanka [31]
3 years ago
13

Suppose that f(x) and g(x) are given by the power series:

Mathematics
1 answer:
lukranit [14]3 years ago
6 0

Answer:

  • c0 = 8
  • c1 = 24
  • c2 = 30
  • c3 = 42

Step-by-step explanation:

It is convenient to notice that the pattern of coefficients that need to be multiplied and summed is a pattern of Xs.

For the constant, c0, only the constants need to be multiplied.

  c0 = 4·2 = 8

__

For the x-term coefficient, the constant of one series needs to be multiplied by the x-term of the other, and the two products added.

  c1 = 4·5 +2·2

  c1 = 24

If you draw real or imagined lines between the coefficients being multiplied, you see that they form an X.

__

For the x²-term coefficient, the above X gets wider, and a vertical | is added. That is constant multiplies x² term and x-term multiplies x-term. The sum has three terms:

  c2 = 4·3 +2·4 +2·5

  c2 = 30

__

For the x³ term, there are now two Xs, one wide and one narrower. Constant terms multiply x³ terms and x-terms multiply x² terms.

  c3 = 4·3 +2·2 +2·3 +5·4

  c3 = 42

_____

This sort of pattern of Xs can be used wherever polynomials (or multidigit numbers) are multiplied. It can help you ensure that all of the products that need to be included in a sum are accounted for.

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Pani-rosa [81]

Answer:

12

Step-by-step explanation:

Distance from (-4,1)to (-1,1) =|-4|-|-1|=3

Side of square =3

Since each side of square is equal.

3x4=12

5 0
3 years ago
Simplify tan9x-tan5x / 1+tan9xtan5x<br> (SHOW WORK)
Charra [1.4K]

Answer:

The simplest form is tan(4x)

Step-by-step explanation:

* Lets revise the identity of the compound angles

- tan(a+b)=\frac{tan(a)+tan(b)}{1-tan(a)tan(b)}

- tan(a-b)=\frac{tan(a)-tan(b)}{1+tan(a)tan(b)}

* Lets solve the problem

- Let 9x = 5x + 4x

∴ tan(9x) = tan(5x + 4x)

- Use the rule of the compound angle

∵ \frac{tan(9x)-tan(5x)}{1+tan(9x)tan(5x)} ⇒ (1)

∵ tan(5x+4x)=\frac{tan(5x)+tan(4x)}{1-tan(5x)tan(4x)} ⇒ (2)

∵ tan(9x) = equation (2)

- Substitute (2) in (1)

∴ \frac{\frac{tan(5x)+tan(4x)}{1-tan(5x)tan(4x)}-tan(5x)}{1+(\frac{tan(5x)+tan(4x)}{1-tan(5x)tan(4x)})tan(5x)}

- Multiply up and down by (1 - tan(5x)tan(4x))

∴ \frac{tan(5x)+tan(4x)-tan(5x)[1-tan(5x)tan(4x)]}{1-tan(5x)tan(4x)+tan(5x)[tan(5x)+tan(4x)]}

- Simplify up and down

∴ \frac{tan(5x)+tan(4x)-tan(5x)+tan^{2}(5x)tan(4x)}{1-tan(5x)tan(4x)+tan^{2}(5x)+tan(5x)tan(4x) }

∴ \frac{tan(4x)+tan^{2}(5x)tan(4x)}{[1+tan^{2}(5x)]}

- Take tan(4x) as a common factor up

∴ \frac{tan(4x)[1+tan^{2}(5x)]}{[1+tan^{2}(5x)]}

- Cancel [1 + tan²(5x)] up and down

∴ The answer is tan(4x)

4 0
4 years ago
What is 9-4x=-23 what's the answer
svetlana [45]
Download Math-way it gives answer for those Type of questions hope this helps
6 0
3 years ago
54 x 120575957 divided by 12
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4 0
3 years ago
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meriva

The Answer Is Y=-8x

This is because x is multiplied by -8 to find y.

5 0
3 years ago
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