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Black_prince [1.1K]
3 years ago
11

I don’t know how to do this one.

Mathematics
2 answers:
irina [24]3 years ago
7 0

Part (a)

The unit circle is centered at (0,0). This point is the origin.

The radius of the unit circle is 1

The term "unit" means "one", which describes the radius length.

=========================================================

Part (b)

The equation of the unit circle is x^2+y^2 = 1

The general equation of any circle is (x-h)^2+(y-k)^2 = r^2

In this case, the unit circle has center (h,k) = (0,0) and radius r = 1.

=========================================================

Part (c)

The following four points are on the unit circle

  • (1,0)
  • (0,1)
  • (-1,0)
  • (0,-1)

As shown below in the diagram. The idea is to plug each given coordinate into the equation from part (b), and solve for the missing variable.

For example, if we know x = 1, then...

x^2+y^2 = 1

1^2+y^2 = 1

1+y^2 = 1

y^2 = 1-1

y^2 = 0

y = sqrt(0)

y = 0

Meaning x = 1 leads to y = 0. So (x,y) = (1,0) is one point on the circle. The other parts are handled in a similar fashion.

serious [3.7K]3 years ago
5 0

Answer:

(a) The unit circle is centered at (0,0) with a radius of 1.

(b) The equation of a circle of radius <em>r</em>, with a center located at (0,0):

<em>x</em>²<em>+ y</em>² <em>= r</em>².

(c) (i) P(1,0)

    (ii) P(0,1)

    (iii) P(-1,0)

    (iv) P(0,-1)

Step-by-step explanation:

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