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3 years ago

Find value of the expressions a=4, b=2 and c=3 then 3a + 2b - 4c

Mathematics

2 answers:

Anna71 [15]3 years ago

6 0

Answer:

Step-by-step explanation:

3a + 2b - 4c

Putting values of a = 4 b = 2 and c = 3

3(4) + 2(2) - 4(3)

12 + 4 - 12

16 - 12

= 4

ArbitrLikvidat [17]3 years ago

3 0

Answer:

Its 4

Hope this helps!

Step-by-step explanation:

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Answer:

$\overline {R'S'} = 3 {\overline {RS} }$

Step-by-step explanation:

The scale factor of dilation of triangle ΔOPQ, S.F. = 3

The center of dilation = Point <em>Q</em>

Therefore;

The length of the segment, ${\overline {S'Q'} }$ = 3 × The length of the segment, ${\overline {SQ} }$

Similarly;

The length of the segment, ${\overline {R'Q'} }$ = 3 × The length of the segment, ${\overline {RQ} }$

By Pythagoras theorem, we have;

${\overline {R'Q'} }^2 = {\overline {R'S'} }^2 + {\overline {S'Q'} }^2$

Therefore;

${\overline {R'S'} }^2 = {\overline {R'Q'} }^2 - {\overline {S'Q'} }^2 = \left ({3 \times \overline {RQ} } \right) ^2 - \left (3 \times {\overline {SQ} } \right) ^2 = 9 \times \left (\overline {RQ} } ^2 - {\overline {SQ} } ^2 \right) = 9 \times {\overline {RS} }^2$

$\therefore \sqrt{ {\overline {R'S'} }^2} = \sqrt{ 9 \times {\overline {RS} }^2}= 3 \times {\overline {RS} }$

$\overline {R'S'} = 3 \times {\overline {RS} }$ .

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Find value of the expressions a=4, b=2 and c=3 then 3a + 2b - 4c​

Find value of the expressions a=4, b=2 and c=3 then 3a + 2b - 4c