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Thepotemich [5.8K]
3 years ago
5

Write an equation for the nth term of the arithmetic sequence. Then find a50.

Mathematics
1 answer:
julia-pushkina [17]3 years ago
4 0

Step-by-step explanation:

Since the sequence above is an arithmetic sequence

For an nth term in an arithmetic sequence

A(n) = a + ( n - 1)d

where a is the first term

n is the number of terms

d is the common difference

From the question

a = 1/3

d = 1/2 - 1/3 = 1/6 or 2/3 - 1/2 = 1/6

Substitute the values into the above formula

That's

<h3>A(n) =  \frac{1}{3}  + (n - 1) \frac{1}{6}  \\  =  \frac{1}{ 3}  -  \frac{1}{6}   +  \frac{1}{6} n</h3>

So the nth term of the sequence is

<h3>A(n) =  \frac{1}{6}  +  \frac{1}{6}n</h3>

For a50 since we are finding the 50th term

n = 50

So we have

<h3>A(50) =  \frac{1}{6}  +  \frac{1}{6} (50) \\  =  \frac{1}{6}  +  \frac{25}{3}</h3>

We have the final answer as

<h3>A(50) =  \frac{17}{2}</h3>

Hope this helps you

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HELPPPPP ASAPPPP!!!!!!
In-s [12.5K]

Hey there!!

Let's take the number as x and y

Given,

The sum of x and y = 12

One number is 2 more than the other

Let's take y = x + 2

Equations

x + y = 12

As we know y = x + 2 , plug the value in

x + x + 2 = 12

2x + 2 = 12

Subtract 2 on both sides

2x = 10

Divide by 5 on both sides

x = 5

y = 2 + x

y = 7

The numbers are 5 and 7

Hope my answer helps!

3 0
3 years ago
Read 2 more answers
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nordsb [41]
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6 0
2 years ago
angle 0 is in quadrant 1 with sin0 = 2/5. Use the Pythagorean identity, sin^2 0 + cos^2 0 = 1, to calculate the value of cos0 as
Gwar [14]
We know that
sin²x+cos²x=1
so 
clear cos x
cos x=(+/-)√[1-sin²x]

in this problem
<span>Angle 0 is in quadrant 1 -----> cos o and sin o are positive
</span>sin o=2/5
cos x=√[1-(2/5)²]----> cos o=√[1-4/25]----> cos o=√[21/25]---> cos o=√21/5

the answer is
cos o=√21/5

7 0
3 years ago
Which expression is equivalent to log Subscript c Baseline StartFraction x squared minus 1 Over 5 x EndFraction?
Harrizon [31]

The equivalent expression of \log_c(\frac{x^2 - 1}{5x}) is \log_c(x^2 - 1) - \log_c(5x)

<h3>How to determine the equivalent expression?</h3>

The logarithmic expression is given as:

\log_c(\frac{x^2 - 1}{5x})

The law of logarithm states that:

log(a) - log(b) = log(a/b)

This means that the expression can be split as:

\log_c(\frac{x^2 - 1}{5x}) = \log_c(x^2 - 1) - \log_c(5x)

Hence, the equivalent expression of \log_c(\frac{x^2 - 1}{5x}) is \log_c(x^2 - 1) - \log_c(5x)

Read more about equivalent expression

brainly.com/question/2972832

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3 0
1 year ago
During the 7th examination of the Offspring cohort in the Framingham Heart Study, there were 1219 participants being treated for
AlexFokin [52]

Answer:

95% confidence interval for the proportion of the population which are on treatment is [0.3293 , 0.3607].

Step-by-step explanation:

We are given that during the 7th examination of the Offspring cohort in the Framing ham Heart Study, there were 1219 participants being treated for hypertension and 2,313 who were not on treatment.

The sample proportion is :  \hat p = x/n = 1219/3532 = 0.345

Firstly, the pivotal quantity for 95% confidence interval for the proportion of the population is given by;

      P.Q. = \frac{\hat p-p}{\sqrt{\frac{\hat p(1-\hat p)}{n} } }  ~ N(0,1)

where, \hat p = sample proportion = 0.345

           n = sample of participants = 3532

           p = population proportion

<em>Here for constructing 95% confidence interval we have used One-sample z proportion statistics.</em>

So, 95% confidence interval for the population​ proportion, p is ;

P(-1.96 < N(0,1) < 1.96) = 0.95  {As the critical value of z at 2.5% level of

                                                         significance are -1.96 & 1.96}

P(-1.96 < \frac{\hat p-p}{\sqrt{\frac{\hat p(1-\hat p)}{n} } } < 1.96) = 0.95

P( -1.96 \times {\sqrt{\frac{\hat p(1-\hat p)}{n} } } < {\hat p-p} < 1.96 \times {\sqrt{\frac{\hat p(1-\hat p)}{n} } } ) = 0.95

P( \hat p-1.96 \times {\sqrt{\frac{\hat p(1-\hat p)}{n} } } < p < \hat p+1.96 \times {\sqrt{\frac{\hat p(1-\hat p)}{n} } } ) = 0.95

<u>95% confidence interval for p</u>= [\hat p-1.96 \times {\sqrt{\frac{\hat p(1-\hat p)}{n} } } , \hat p+1.96 \times {\sqrt{\frac{\hat p(1-\hat p)}{n} } }]

    = [ 0.345-1.96 \times {\sqrt{\frac{0.345(1-0.345)}{3532} } } , 0.345+1.96 \times {\sqrt{\frac{0.345(1-0.345)}{3532} } } ]

    = [0.3293 , 0.3607]

Hence, 95% confidence interval for the proportion of the population which are on treatment is [0.3293 , 0.3607].

6 0
3 years ago
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