Answer:
For the number 5 the multiples are 5, 10, 15, 20, 25
For the number 7 the multiples are 7 ,14 ,21 ,28 ,35
For the number 12 the multiples are 12 ,24 ,36 ,48 ,60
Last for the the number 16 the multiples are 16, 32, 48, 64, 80
Step-by-step explanation:
HAVE A GOOD DAY!
Pretty simple. He needed 6.7 gallons to fill the tank. At 3.80/gallon, he spent $25.46
The solution to the given quadratic equation is;
x = -2 and x = 1/5
<h3>Roots of quadratic Equation </h3>
We are given the quadratic function;
(x + 2)(5x - 1) = 0
In quadratic functions, when it is expressed as;
(x + a)(x - b) = 0, what this means is that the factors of the quadratic equation or polynomial are; (x + a) and (x - b)
What that means is that the roots will be gotten from;
(x + a) = 0 and (x - b) = 0
Thus, applying the concept above on roots of a polynomial to our question, we have;
(x + 2) = 0 and 5x - 1 = 0
Solving them gives us;
x = -2 and x = 1/5
Read more on roots of quadratic equation at; brainly.com/question/8649555
Co-terminal angle = 456 - 360 = 96 degrees
Answer:
(a) (a² +3a -1)(a² -3a -1)
Step-by-step explanation:
The constant term of the product of the factors will be equal to the product of their constants. Since you want that product to be +1, the signs of the factor constants must be the same. That eliminates choices (c) and (d).
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To tell which of choices (a) and (b) is correct, we can compute the squared term in their product. Let's do it in a generic way, with the constant (±1) being represented by "c".
We want the a² term in the product ...
(a² +3a +c)(a² -3a +c)
That term will be the result of multiplying both sets of first and last terms, and adding the product of the middle terms:
(a²·c) +(a²·c) -9a² = a²(2c-9)
So, we want the factor (2c-9) to be -11, which means c=-1, not +1.
The correct factorization of the given expression is ...
(a² +3a -1)(a² -3a -1) . . . . matches choice A
